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%- x! ]4 O* g1 t& ^1 D& t
G40 G17 G49 G80 G90
7 t% u% D- C( C$ f0 Z- tM05
* c+ R- a, I. S+ YM09
& f( }# `; w- z# qG91 G28 Z0.0
6 L' g6 l- u. O0 P- j" ]& S# z( XT1M067 ]6 E$ U3 ]: ~3 T2 N* ]
M01
( A: F3 g& j5 U# M, u( h7 t(NAME :SPHERICAL_MILL )3 T# g# V. ]; b0 i$ U
G00 G90 G54 X37.6 Y20. S3000 M03. g4 ?* d! P/ b8 y
G43 Z16.6 H01
0 ^# b: D) Q% c- }0 s' BZ-30.4; T X2 p6 A2 E" g6 y
G01 Z-33.4 F250. M085 o& V& y4 }# N# [1 r( ]2 Z
X31.67 f+ K! e% l3 n: a/ |% ~
G02 I-8.6 J0.0
" W6 c; s! h" L# r9 L: k7 `G01 X37.67 E; l4 Q( {, {! w# g7 p
Z-30.4
2 m+ h W, ^8 q0 I0 {7 I8 X% B+ yG00 Z16.6
8 Q: Q) I! t4 E7 h9 f( GG00 Z-30.4& j. `: o7 r3 _% d$ ?
3 v) ^" n4 ?! M/ `6 }G00 G90 G54X37.6 Y20. S2500 M03 u3 T3 \: V3 {* q! r: r
G43 Z-33.4 H01" A: ~5 ?1 `! y% _
X31.6; K. s0 t( o; I& K" w" [
G02 I-8.6 J0.0
& G/ `0 [7 y' Z% N; j! n- ]1 cG01 X37.64 F1 D; a) ~# t+ c a6 |2 j0 x
Z-30.4
# v' F. X. q' e* l IG00 Z16.6
T& O% a' E T7 M, v2 N8 Q( y) FM05
* [3 ?; p% ~. u+ E# T4 BM09# }+ M/ d) I6 J7 l" ~8 E0 `
G91 G28 Z0.07 q0 q5 A' R6 O6 V7 N
M30
: w$ X3 I/ H& G%
: t* V) q6 {1 F* t* a5 h9 M! i同一把刀(不换刀),两个操作之间怎么样让他每次都能输出坐标系G54,和G43长度补偿呢(像红色部分那样)?, @+ e$ h% v5 ?/ \ \5 E
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