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初学ug二次开发的GRIP语言,想用GRIP语言画个渐开线花键,但是关于曲线剪切命令不会使用,总算让我试出来了,先来个小例子讲解一下吧!我要将ln3用c2和ln1裁剪,
+ e. v4 [: Q+ C& dgrip语言剪切命令CRVTRM命令格式:
; I7 ^' @. i9 g" f4 M1 UObj=CRVTRM/curve,REF,{pt1|x,y,z},$5 u' i: t: o4 L
FIRST,limit1[,REF,{pt1|x,y,z}]$, Z" L/ _2 W2 c4 \: f2 U! r
[,INT,{pt2|x,y,z}][,NOTRIM]$( T" s9 o; |- u& U% ?% j# \6 W
[,SECOND,limit2[,REF,{pt1|x,y,z}]][,INT,{pt2|x,y,z}][,NOTRIM]]$ q; \) p6 N9 B$ p0 ?
,STATUS,status[,IFERR,label:]
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- C1 D# `( n" W% `- @: U! `0 `9 w具体实现代码如下,直接可以放到grs中运行!
" H' z3 u: Y% I- E6 G. ~# SENTITY/SPLNP(4),SPLN,SPLNRS,ARC1P(3),ARC1,ARC2P(3),ARC2
, k+ h9 v* Y9 R' oENTITY/LINE1P(2),LINE1,LINE2P(2),LINE2,LINE3P(2),LINE3" `' O5 p: {3 Q* U- G
NUMBER/STAT
8 [8 E% E( o8 H/ U: F0 a( i C [9 f. G$$ CREATE LINES, ARCS, AND SPLINES TO TRIM+ `& ^* B: ?; D# H1 M6 c4 X: R7 \
LINE1P(1) = POINT/-1,5,0
, G* D; f& B5 N1 P- d) jLINE1P(2) = POINT/-1,-1,07 J! ]1 U4 ]/ L- R
LINE1 = LINE/LINE1P
) c: Y( ?* G6 H5 lLINE2P(1) = POINT/1,5,0
& T2 Z8 q7 }/ M6 {4 A, u# b9 ZLINE2P(2) = POINT/1,-1,0
, {2 T$ b6 ]% n/ X( h' \+ V; @0 p5 _LINE2 = LINE/LINE2P, h& Y% }. `2 b3 s1 x
LINE3P(1) = POINT/-2,1,06 ?7 Z; j' D8 L7 X- a( u0 K) {) @
LINE3P(2) = POINT/2,1,0, `1 X$ E2 l* \. L
LINE3 = LINE/LINE3P
+ T2 |* I2 p( T p9 F% K4 k. YSPLNP(1) = POINT/-2,2,0$ a& b5 W( f. w
SPLNP(2) = POINT/-0.5,2.5,04 c; n5 B$ F% E0 J3 t" m
SPLNP(3) = POINT/0.5,1.5,0
! s2 X4 s) B% S3 mSPLNP(4) = POINT/2,2,00 h$ @: \, u" t, |/ M% u
SPLN = SPLINE/SPLNP5 p# e2 Z ?- ~& v$ D3 L; z9 r! b
ARC1P(1) = POINT/2,4,0
) E: i1 t3 S3 [0 I: e! |1 WARC1P(2) = POINT/0,4.5,04 D$ M8 d, c0 f0 B. f
ARC1P(3) = POINT/-2,4,0( y+ \8 D5 I, S% g( s: Q3 E/ p
ARC1 = CIRCLE/ARC1P
3 q* K# T5 Y" e0 M6 fARC2P(1) = POINT/2,3,0( c2 S6 @. r o
ARC2P(2) = POINT/0,3.5,0
- Y, X& i; h4 ]ARC2P(3) = POINT/-2,3,0
6 B) j/ q% r9 ?! y$ U% k/ QARC2 = CIRCLE/ARC2P
* R8 V+ ~. v/ F. W* Y9 o$$用LINE1剪去ARC1的右边; q# }6 T" h" j8 k2 O6 ]: `2 W* B
CRVTRM/ARC1,REF,ARC1P(2),FIRST,LINE1,INT,LINE1P(1),NOTRIM,STATUS,STAT,IFERR,ER1:( m# l: _- g7 E* X5 t
$$用LINE2剪去ARC2的左边
3 A- S$ a% |+ J3 nCRVTRM/ARC2,REF,ARC2P(2),FIRST,LINE2,INT,LINE2P(1),NOTRIM,STATUS,STAT,IFERR,ER1:- G( i# O. n: Z- d4 L! K- J* m
$$用LINE1、2剪去SPLIN的中间,是唯一产生另外线段SPLNRS的裁剪6 z+ b0 P# c) W! q( f ~
SPLNRS=CRVTRM/SPLN,REF,SPLNP(2),FIRST,LINE1,INT,LINE1P(1),NOTRIM,$, d+ j9 {* l; }; n& O. T
SECOND,LINE2,INT,LINE2P(1),NOTRIM,STATUS,STAT,IFERR,ER1:
2 \( P- f! o9 i* Q% c$$LINE1、2、3一起剪2 N+ f7 {: {9 b: l, a, |/ {' ~5 S
CRVTRM/LINE3,REF,LINE3P(1),FIRST,LINE1,REF,LINE1P(2),$' l/ s' r8 I/ M' I
SECOND,LINE2,REF,LINE2P(2),STATUS,STAT,IFERR,ER1:
( v- V! {) e3 |9 e) K" k9 pJUMP/TERM:
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0 K; ~4 |/ `" a' T3 }MESSG/'CRVTRM ERROR STATUS = ',ISTR(STAT)7 _: v: `8 j$ d
TERM: HALT |
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