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初学ug二次开发的GRIP语言,想用GRIP语言画个渐开线花键,但是关于曲线剪切命令不会使用,总算让我试出来了,先来个小例子讲解一下吧!我要将ln3用c2和ln1裁剪,
4 D+ W4 A; r0 @; qgrip语言剪切命令CRVTRM命令格式:( w$ D/ _9 D8 b9 k2 U* E3 d
Obj=CRVTRM/curve,REF,{pt1|x,y,z},$) Q# \1 p5 D( _6 J1 n
FIRST,limit1[,REF,{pt1|x,y,z}]$& _( t* `7 m3 {) m8 W$ ^) S3 d
[,INT,{pt2|x,y,z}][,NOTRIM]$
: C8 }3 ~ e& u[,SECOND,limit2[,REF,{pt1|x,y,z}]][,INT,{pt2|x,y,z}][,NOTRIM]]$& v$ d, N' A& k* ?$ c/ c; W. V
,STATUS,status[,IFERR,label:]0 K! s X, b# _7 X
, H4 r" A9 V3 e* j* G* ?& g; Z4 c# e具体实现代码如下,直接可以放到grs中运行!4 j- V) i" ~9 p
ENTITY/SPLNP(4),SPLN,SPLNRS,ARC1P(3),ARC1,ARC2P(3),ARC2- r, y: R2 S- t( x) ~+ y0 q
ENTITY/LINE1P(2),LINE1,LINE2P(2),LINE2,LINE3P(2),LINE38 Y5 Y8 u0 t6 W+ ]) X7 z& t M
NUMBER/STAT) P2 ~4 O( `/ w) @6 w2 |
$$ CREATE LINES, ARCS, AND SPLINES TO TRIM
4 I- h' L- x2 J$ BLINE1P(1) = POINT/-1,5,0
8 c7 R6 L% S* H. }6 e% DLINE1P(2) = POINT/-1,-1,09 ?0 H( \. ~$ x' e1 ]. v
LINE1 = LINE/LINE1P+ g' }5 M$ A" N- n; U% B
LINE2P(1) = POINT/1,5,0$ n7 G$ u: _3 M
LINE2P(2) = POINT/1,-1,0
% c* l9 e+ c. _LINE2 = LINE/LINE2P
, A* _$ B5 t. t9 e; ^LINE3P(1) = POINT/-2,1,0, }& ~6 t0 x+ ~/ c
LINE3P(2) = POINT/2,1,0
- x! e" _6 s- T7 qLINE3 = LINE/LINE3P/ `4 m- J) R0 q: r. ]6 G
SPLNP(1) = POINT/-2,2,09 P7 R8 z4 k% L+ s1 [ H! W/ @' k
SPLNP(2) = POINT/-0.5,2.5,0% S D$ l5 [0 M
SPLNP(3) = POINT/0.5,1.5,04 R9 Z& }* p% _& D
SPLNP(4) = POINT/2,2,0; v. ]3 T6 {8 F
SPLN = SPLINE/SPLNP
) n( P! q; @# _! NARC1P(1) = POINT/2,4,0
4 d: t. R- t) G4 Z( ~ARC1P(2) = POINT/0,4.5,0
! l5 j9 z3 j# @" b* yARC1P(3) = POINT/-2,4,0# X _4 ^+ L2 Z. P9 m4 [
ARC1 = CIRCLE/ARC1P
; m& V! V. [4 w1 A9 y3 KARC2P(1) = POINT/2,3,0/ A+ R$ D% G3 D6 i' Z/ n7 y" ?
ARC2P(2) = POINT/0,3.5,0 U- M# s9 \+ X% h0 s; [2 a
ARC2P(3) = POINT/-2,3,07 G8 e) n# W: \' D2 P9 ~
ARC2 = CIRCLE/ARC2P$ `4 o# M4 Z( g/ _, ?1 R
$$用LINE1剪去ARC1的右边
5 |: o" y/ e) v- Z& ZCRVTRM/ARC1,REF,ARC1P(2),FIRST,LINE1,INT,LINE1P(1),NOTRIM,STATUS,STAT,IFERR,ER1:
0 K- q9 x+ U& m1 W- Z4 n6 o' ^$$用LINE2剪去ARC2的左边: f' i+ P- |/ M. K& R
CRVTRM/ARC2,REF,ARC2P(2),FIRST,LINE2,INT,LINE2P(1),NOTRIM,STATUS,STAT,IFERR,ER1:1 ?) {2 k1 Q: `4 h* X( b
$$用LINE1、2剪去SPLIN的中间,是唯一产生另外线段SPLNRS的裁剪
0 k$ \6 v/ `( Z$ j# M+ ~$ i, SSPLNRS=CRVTRM/SPLN,REF,SPLNP(2),FIRST,LINE1,INT,LINE1P(1),NOTRIM,$- Z4 S+ t4 k/ b; o
SECOND,LINE2,INT,LINE2P(1),NOTRIM,STATUS,STAT,IFERR,ER1:) z! G! J* V8 C* C% i! P
$$LINE1、2、3一起剪
/ x" z+ Y3 z9 d1 B, \# oCRVTRM/LINE3,REF,LINE3P(1),FIRST,LINE1,REF,LINE1P(2),$% q3 J/ A+ y9 H! v
SECOND,LINE2,REF,LINE2P(2),STATUS,STAT,IFERR,ER1:
7 y1 p; U) }# C" e: NJUMP/TERM:9 u0 |$ J E+ y: d/ L
ER1:
: G" M; Y$ i% n- ~MESSG/'CRVTRM ERROR STATUS = ',ISTR(STAT)! T* v, b) m' G& ]& |- T$ l
TERM: HALT |
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