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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!
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但现在的一个问题是怎样选择图形中已经有了的实体如图:
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小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!
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源代码:1 A! s; l; m% S; w! z
entity/a1(100),pt(100)
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* T2 j, G1 k2 I# v' Wl1:: M& z# [5 @- H+ i; L
gpos/'选择一个点',x,y,z,resp; h5 b+ `6 j$ x
jump/l1:,end:,,,resp
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+ }( R% B5 j! d- ?6 [) P$ f8 n0 P param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp/ U% _# N$ L# p# ?2 W
jump/l10:,end:,,,resp, i1 \( T: g9 W& y% w# }* r: _& g
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a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1- H! c' R& \ l7 _7 I. y
a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1 [; g8 }1 w2 B8 x- ?7 |$ t* {) ]
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-19 P% Q) a1 D3 g: ?
a1(4)=unite/a1(1),with,a1(2)
% c1 K9 f- {, K' o& d. l( Xa1(5)=unite/a1(3),with,a1(4)
" \. g5 v C% @% k! Oa1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-13 x- t1 o" V# b6 B- P
a1(7)=unite/a1(5),with,a1(6)
. Z7 d0 m3 Z4 a+ Q$ bpt(1)=point/x+11.53,y,z-30
: `$ S; x. C1 T1 y) u8 E* Gblend/a1(7),chamfr,14,pt(1)) f9 _& k% U: M* a' E
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1
! z: l3 V' ?% C5 U* la1(9)=unite/a1(7),with,a1(8)0 r' f3 Y c8 n4 K
a1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,70
: [, I4 {( p. q1 w# c4 Va1(11)=subtra/a1(9),with,a1(10)
$ v- B$ W* T& c+ }pt(2)=point/x+35,y,z-22.67767. |1 b3 G0 P+ l# H
blend/a1(11),chamfr,17.32233,pt(2)2 u) |1 U0 P6 V; g2 x9 y
a1(12)=solsph/origin,x,y,z-5,diamtr,50
% Y, b \# J* w8 ya1(13)=subtra/a1(11),with,a1(12)
% m* U# p" n0 l% A" ~' R; ^a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009
) s! H6 l/ v2 a" Ma1(15)=subtra/a1(13),with,a1(14)
! Y: F5 Q( q: v; Ypt(3)=point/x,y+49.9,z+10* Z- @ z' X7 |5 C4 x1 J% ?0 c
blend/a1(15),chamfr,0.5,pt(3)
; S) t* e/ [$ l$ i! u+ Y/ Spt(4)=point/x,y+62.5,z/ ]5 Z7 u+ d) h' z+ {
blend/a1(15),chamfr,0.5,pt(4)
% ~) N' H6 i( g, bpt(5)=point/x,y+62.5,z-15! Z2 O5 p5 R- I3 M# T9 [
blend/a1(15),chamfr,0.5,pt(5)
! ^3 P+ ~0 u; U& Q2 A3 ^8 |pt(6)=point/x,y+50,z-30
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pt(7)=point/x,y+35,z+10
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delete/pt(1..100)) ^3 {* p- `! `5 j" X
a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
1 V) i( B( @- ?8 z: q, j0 P% J$ ]a1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-1
T% A8 b3 `( I) aa1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1
% n. _) Q( p# @5 oa1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-1( |8 e- s& t$ X, f2 ^5 R) n3 _
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
6 E2 y9 b4 }+ j4 A1 U0 c) Pa1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1' O' D0 a# X/ y+ k
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
% O& Q& W a8 i, H. n. Ia1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
+ t% l2 L: Q+ n& N2 Za1(24)=subtra/a1(15),with,a1(16)
+ P1 `8 v# `: f: ga1(25)=subtra/a1(24),with,a1(17)
& K6 [2 i) g% l& R8 B3 J7 Ha1(26)=subtra/a1(25),with,a1(18)7 X' A+ r2 H3 ]0 G; \" I1 M7 p) d
a1(27)=subtra/a1(26),with,a1(19)5 W2 A& N; T, z Z F: ?" R" m
a1(28)=subtra/a1(27),with,a1(20)
3 J1 N% ~/ b: S' ^7 {a1(29)=subtra/a1(28),with,a1(21)
i1 \6 W x& F5 O( aa1(30)=subtra/a1(29),with,a1(22)
`" D W5 H. pa1(31)=subtra/a1(30),with,a1(23)
- t- r* K0 I: f5 W! ?8 F) b&color(a1(31))=121
1 g8 x5 \9 B9 k/ }) l1 H) ^&name(a1(31))='JZ'
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