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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!
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7 ^+ P! T5 [$ r4 j+ A! Q" E2 Z但现在的一个问题是怎样选择图形中已经有了的实体如图:
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5 N* @" U6 w& v5 U小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!
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9 ~9 c2 [3 g" e2 S x `9 Q源代码:: T, _/ U5 Z0 A7 Y' x
entity/a1(100),pt(100)
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l1:: l$ N$ f6 e' I
gpos/'选择一个点',x,y,z,resp
5 M7 C( a5 @2 O8 n9 W jump/l1:,end:,,,resp
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param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp: }( j! _- {) J0 X. |; ^
jump/l10:,end:,,,resp3 |4 t0 t3 n3 I& k, j
l2:
2 c/ P. T* I6 J0 A+ w. b# ba1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1# S# R2 }8 e* H4 B" a. ^
a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1
X" o* D: f H2 H5 N$ L, da1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-1
& I" S* E6 Y8 y/ t/ l3 k* }a1(4)=unite/a1(1),with,a1(2)
* J8 l* r( q1 \/ g: F3 _a1(5)=unite/a1(3),with,a1(4)
7 ^+ r6 P: z$ p9 X2 ia1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-12 h& n4 i% f7 h4 z2 P0 x1 Y8 F
a1(7)=unite/a1(5),with,a1(6)6 X3 ^/ {8 B' o$ J7 L
pt(1)=point/x+11.53,y,z-30
" P! z% o8 G$ Jblend/a1(7),chamfr,14,pt(1)/ C4 L8 _ S! o# N" q
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1- U# H# @ S' e. J6 I
a1(9)=unite/a1(7),with,a1(8)- I( N. J% S% C
a1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,70
3 k) X3 u$ U; Ua1(11)=subtra/a1(9),with,a1(10)
9 v& A5 g. T8 \5 b4 p8 Ipt(2)=point/x+35,y,z-22.67767
) z. t! z2 d) ], D' a' Sblend/a1(11),chamfr,17.32233,pt(2)
- s0 Z O' r$ o( S" z- a7 ^a1(12)=solsph/origin,x,y,z-5,diamtr,503 b' s8 |9 x3 s& [. n
a1(13)=subtra/a1(11),with,a1(12)& H7 R, g! t, c# ]% {0 m
a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009* I% X# F5 N# m1 @
a1(15)=subtra/a1(13),with,a1(14)
% T) H1 X( g- h- Apt(3)=point/x,y+49.9,z+109 `" L( V" X5 K9 x
blend/a1(15),chamfr,0.5,pt(3)1 j% P' |: D( Y+ Q) s6 F
pt(4)=point/x,y+62.5,z- y" G3 ]1 i& _: b. _
blend/a1(15),chamfr,0.5,pt(4)$ L7 p2 i3 X$ p6 T0 }
pt(5)=point/x,y+62.5,z-15' O" K( m7 Y: b1 [! B) V8 d( }
blend/a1(15),chamfr,0.5,pt(5)' Y* l V2 c8 A* D" o
pt(6)=point/x,y+50,z-30# A/ D- G/ K5 u% e5 k, e; s
blend/a1(15),chamfr,0.5,pt(6)& j$ n0 c% c8 Z
pt(7)=point/x,y+35,z+10
9 A: [$ H h) L7 D8 N c, vblend/a1(15),chamfr,0.5,pt(7)2 R4 c: f0 D" m
delete/pt(1..100)
9 }1 K1 U# o6 @- Ja1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
8 i) o. r# O u* d: d* i( c3 Ma1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-1
0 I: V+ A8 B: Y6 `$ X3 Ea1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1
$ E# P# U# [2 M# Y$ |& z; R& d# sa1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-1) l0 e+ _4 U, ^# x2 z5 _0 h! p! L$ \. Y
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
* f" ~7 n8 |3 ha1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1
4 r1 v5 N# A7 _( R5 aa1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1# L5 v7 t* t/ W# P! P, X0 ?
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
5 q; Q: T: \) b$ L" x- Ia1(24)=subtra/a1(15),with,a1(16)
% a/ V" `! ~) i. e% M2 h O( \a1(25)=subtra/a1(24),with,a1(17)
/ R! m! o. s" u% Fa1(26)=subtra/a1(25),with,a1(18)
& e" X0 U R+ o% ]8 \( [6 ^a1(27)=subtra/a1(26),with,a1(19)
9 j- p/ H6 i3 U$ |0 K5 Ia1(28)=subtra/a1(27),with,a1(20)
, X1 e/ R, P9 f j2 n% i+ G; ra1(29)=subtra/a1(28),with,a1(21)
6 D6 y1 w: J- J% k2 Ma1(30)=subtra/a1(29),with,a1(22)" Z& Y0 T: |1 W8 P2 L" F
a1(31)=subtra/a1(30),with,a1(23)
p& m8 |' v4 F&color(a1(31))=121; b0 k; ?1 x5 i g9 ~. S9 @
&name(a1(31))='JZ'
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% d4 X; R: |2 q4 j! Ejump/l1:
5 F. {7 w3 m( ?" Q4 B, c9 yend:9 r, |7 p( c$ a: X) G# B' z
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