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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!1 S' c7 G: v8 [
3 V6 d; `8 D$ t! d# C& y+ g但现在的一个问题是怎样选择图形中已经有了的实体如图:
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小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!
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! _% ^ c5 U. j/ n% u源代码:
5 N7 }- V# F( p- tentity/a1(100),pt(100)
4 B+ q+ C- }0 a0 L, |* }6 v! U% Q4 [3 Q3 x; u$ [
l1:
, p- d' i3 _& x! m' |, ^. ^( u gpos/'选择一个点',x,y,z,resp) J& I! X4 D* O# ]
jump/l1:,end:,,,resp# z0 o% C4 W+ b" _% e4 }' ~
l10:" y; r" _. _+ V x, `, \
param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp+ W. O- E3 W$ z) h7 n
jump/l10:,end:,,,resp4 ~: G# B; |+ x4 z" I
l2:
) L" x/ U4 D8 @a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,12 z5 B+ Q! p( i/ k% |
a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1
; P$ V- D! B8 F6 L# b3 |a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-1- K0 |7 O" w" e
a1(4)=unite/a1(1),with,a1(2)
$ `' b( F5 f9 k( _- e4 Ka1(5)=unite/a1(3),with,a1(4)
; R3 D/ a7 Q% ^" n0 U. ma1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-10 s. j& K) H6 W# ^; J3 c% E6 k
a1(7)=unite/a1(5),with,a1(6). N' Q d4 A( u1 v7 ?) C" n6 e# B
pt(1)=point/x+11.53,y,z-30
$ ^) N$ m4 U8 o* \( b$ I. vblend/a1(7),chamfr,14,pt(1)) y- [$ d1 G! a( I9 {8 E r
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,15 X/ I' U/ @1 T8 Y( g
a1(9)=unite/a1(7),with,a1(8)
) A+ p: j5 L8 ]% B! Q/ g( Oa1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,709 r F1 v0 `* ]6 q
a1(11)=subtra/a1(9),with,a1(10)& @- Z; a+ l L
pt(2)=point/x+35,y,z-22.67767. `6 K3 [+ u4 A: |* ^6 a
blend/a1(11),chamfr,17.32233,pt(2)) U& ]1 O% C/ U4 K( y g' h
a1(12)=solsph/origin,x,y,z-5,diamtr,50
& H2 D; e* L& p- U5 }2 J: n: Aa1(13)=subtra/a1(11),with,a1(12)
9 p* I! O; r* m: {# z- ya1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009
9 w0 ^9 D' T$ ?+ o1 U1 _0 Fa1(15)=subtra/a1(13),with,a1(14)3 _/ i" M; Z: D- D
pt(3)=point/x,y+49.9,z+10- t! g4 y- W0 w, n/ Z- S0 A
blend/a1(15),chamfr,0.5,pt(3)8 \! Y6 h" }0 g/ ~1 s& K
pt(4)=point/x,y+62.5,z- e. U% ]+ N( \* r( e- P
blend/a1(15),chamfr,0.5,pt(4)7 J8 S6 M( k$ F: z% |" T5 L
pt(5)=point/x,y+62.5,z-15
4 F3 O& c/ E3 w- bblend/a1(15),chamfr,0.5,pt(5)
( N/ E4 A, X# B8 \' r# X: Hpt(6)=point/x,y+50,z-30! C, X* x+ _( n+ z" Y
blend/a1(15),chamfr,0.5,pt(6)
" o" L3 I& b+ b) |- y+ m. _ [1 Z6 W6 fpt(7)=point/x,y+35,z+10" y5 i; N9 I" k3 f7 b% V1 [
blend/a1(15),chamfr,0.5,pt(7)
# o& _, h) Y% ]delete/pt(1..100)
' P: R4 [, c5 Ea1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
6 m- I3 o3 A" n) g0 B. k8 }a1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-15 [, }6 J, G$ ~3 i* `
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1
1 \4 S5 I/ f/ S* l2 u- b# I( b( xa1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-13 J" [8 n' K4 F2 t* P1 E
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
- e7 g* \8 f3 _6 t, C8 L! { i3 Aa1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1
" w( [9 w$ F' w2 _' l: L' pa1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-12 }! x9 q0 d6 L$ u' E
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
k1 n, `# L& j U5 @9 N, ra1(24)=subtra/a1(15),with,a1(16)
( Z- d6 k( L* p. z+ }1 A( O2 d; [a1(25)=subtra/a1(24),with,a1(17)8 E9 \: Q+ s+ c7 P2 \6 G9 ^ e" O
a1(26)=subtra/a1(25),with,a1(18)8 K+ e. w4 `- n$ q1 U( _' r% F
a1(27)=subtra/a1(26),with,a1(19)
" e) G# L' K! L" u: z3 q; s; M- ia1(28)=subtra/a1(27),with,a1(20)
: ~- d* ~0 R; |2 P# K0 za1(29)=subtra/a1(28),with,a1(21); A8 m5 m( F, Y
a1(30)=subtra/a1(29),with,a1(22); W7 m. e8 ^ C$ F9 h; E
a1(31)=subtra/a1(30),with,a1(23)& t3 Q: u; _: u9 |& E
&color(a1(31))=121
. |! Q, T' ?' c&name(a1(31))='JZ'
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jump/l1:
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