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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!# X& I" ^4 m* }; [$ s) z* P3 e
: g1 V9 T7 C, {, q9 B2 N但现在的一个问题是怎样选择图形中已经有了的实体如图:! ]& q' p% a3 x0 W* X
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+ |2 ~8 b* H/ e/ j% V" a, `. I; i4 [; @) l9 K S
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小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!8 r. D' N q) Z5 [8 o7 r; i
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源代码: m$ V5 }2 R8 }* ]) ]( _
entity/a1(100),pt(100)& L2 y& r, c% D( } {& n. ?2 j8 K
* q& }) c% K8 S' r ll1:; _. q1 k) ]* ]/ S0 ]8 |- C
gpos/'选择一个点',x,y,z,resp
* }3 s% c" Y& G; |$ U g" L9 q jump/l1:,end:,,,resp( c9 G" f0 D/ ]3 i9 }9 L$ L3 _4 |
l10:
: _' X6 N b* f param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp
- i3 ~: o& r7 H: K jump/l10:,end:,,,resp S6 c. Q. l+ ^/ |( _
l2:
6 _! q K4 U! x4 ^% c Qa1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1
3 I8 i; ]* Q5 F! K- ]" K8 A& Q0 Ja1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-10 ?' ~9 T6 v9 S. H7 c% N
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-17 G! X0 l% ~6 Y' M! w
a1(4)=unite/a1(1),with,a1(2)
% C9 w* b: G; ~- Ma1(5)=unite/a1(3),with,a1(4)/ E9 |& @; O6 a6 b* n2 h
a1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-1
- p Y% {4 f. B( J3 Ka1(7)=unite/a1(5),with,a1(6)
/ |0 J- R( w& F; A' dpt(1)=point/x+11.53,y,z-307 W% v, A: M1 F0 P, ^
blend/a1(7),chamfr,14,pt(1)3 ?( e' s; B% C+ D
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1
4 w* b$ j0 ?3 G$ ^2 Sa1(9)=unite/a1(7),with,a1(8)
6 G9 r }' S7 X1 z# q( ^$ ]# L7 _a1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,70' ^; t* A N3 R# R: r
a1(11)=subtra/a1(9),with,a1(10)
' F" `# ?( K) m/ O( ~) b J8 S7 s6 fpt(2)=point/x+35,y,z-22.677676 d; I" ?4 V+ i( b# l* \
blend/a1(11),chamfr,17.32233,pt(2)
4 `' F* [; ?4 F" [6 Ta1(12)=solsph/origin,x,y,z-5,diamtr,50
! j) `, X1 s: M. B" Pa1(13)=subtra/a1(11),with,a1(12)
2 X& Q- z7 Y# c5 S7 V- Wa1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009
* C) q" V9 ?7 Ga1(15)=subtra/a1(13),with,a1(14)
: K M! _% u; l1 x5 k3 D! p. L1 _pt(3)=point/x,y+49.9,z+10
" q" T! q6 {4 xblend/a1(15),chamfr,0.5,pt(3)% |$ e8 O! P, B8 ^
pt(4)=point/x,y+62.5,z! Y! f! c% ]; y" h; P8 b$ g
blend/a1(15),chamfr,0.5,pt(4)
6 Q. i' K: w8 g- |6 Z- f& h4 Wpt(5)=point/x,y+62.5,z-15
; |0 @6 H* S4 v% s3 hblend/a1(15),chamfr,0.5,pt(5)9 O. K h" u: u. L+ H2 u5 r
pt(6)=point/x,y+50,z-30
5 h& ~( T# ~ \blend/a1(15),chamfr,0.5,pt(6)# N$ m( E5 I, I3 n- b: t2 Z* c
pt(7)=point/x,y+35,z+10
( x9 g2 N+ B: n0 g- u: }blend/a1(15),chamfr,0.5,pt(7): o- E# I! g4 T# X
delete/pt(1..100)+ q3 Y/ z3 G0 d( d
a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
( w6 T. v8 h) `; }; T" pa1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-1" G6 m \0 S5 N0 z- A L1 [, |
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-17 h* S: U! B2 z) Z
a1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-17 _8 x" D2 L7 S1 ]: ?0 H
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
' D' S# ^6 Z3 B3 S9 v4 _a1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1, i9 B; i. h! X6 T, X: h) J% B
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-16 P$ u& o. M+ T1 a1 h7 A
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1; m* F' P' J% r0 M8 v
a1(24)=subtra/a1(15),with,a1(16)7 j( q+ H4 K, A! ^ U
a1(25)=subtra/a1(24),with,a1(17)
- v6 f! l+ T" D ba1(26)=subtra/a1(25),with,a1(18)' i3 {) Q `" e( |6 {
a1(27)=subtra/a1(26),with,a1(19)+ A* V( `2 z1 Z# Z
a1(28)=subtra/a1(27),with,a1(20)2 P7 V% e% k3 _7 A% e$ @
a1(29)=subtra/a1(28),with,a1(21)+ R8 F* @# v- m* m) i; P
a1(30)=subtra/a1(29),with,a1(22)0 z3 l& g' @6 s- {4 g; c; e
a1(31)=subtra/a1(30),with,a1(23)) U. Y* s1 h3 O) p. B. h, r6 C1 `
&color(a1(31))=121
2 U" l! O+ Q7 L4 J&name(a1(31))='JZ'+ ]( |& f! Q) B' D e% ?9 W
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jump/l1:
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