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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!1 G+ x' C2 [+ J6 K8 g- M( [
# K1 ]' s- i/ U但现在的一个问题是怎样选择图形中已经有了的实体如图:4 x- n+ x9 `7 \) l- S
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小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!5 L H7 z" a+ f: T
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I4 J& v3 n6 v, y* V- e7 I2 h源代码:
" G) `; {' D5 h/ M8 f) gentity/a1(100),pt(100)3 B" H& Q, r8 m# o( m
/ k; r. Z3 I4 |& I% a; {l1:* l3 h" l! C; ]) v
gpos/'选择一个点',x,y,z,resp
5 ^# f3 r2 c" x jump/l1:,end:,,,resp
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% d8 C$ p; d3 W# d param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp
$ \0 L4 ^' E4 j5 Z, r6 d6 ~* ^ jump/l10:,end:,,,resp
( a) U- {! q5 n- H/ Hl2:" W; K4 u% v: a2 L$ I. o; ?* F3 R
a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1
. J: Q5 S; T" La1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1( c3 ^/ P) _- k! y( B% |
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-12 I" S! u* |" |$ |! C8 n: ~
a1(4)=unite/a1(1),with,a1(2)
4 j+ F- \) Q- H6 J; ~a1(5)=unite/a1(3),with,a1(4)& k( Z0 ~/ Q( T# A& }) ?: S
a1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-1
; q* C& _. L& I4 b/ n- \% ~a1(7)=unite/a1(5),with,a1(6)$ r- z- C5 ]9 f1 R$ F8 o
pt(1)=point/x+11.53,y,z-30) W0 S a$ m; d- i. J
blend/a1(7),chamfr,14,pt(1)! Q5 }4 q* }1 Y# o% n2 o9 [% Z
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1
' y6 `2 M" X4 E8 l2 Q' R) t- Ta1(9)=unite/a1(7),with,a1(8)
% S1 u& ~; E" a& Pa1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,707 P* k8 l# J4 c% @* N% h
a1(11)=subtra/a1(9),with,a1(10): P2 W/ I" ]" }; J
pt(2)=point/x+35,y,z-22.67767
* N& D0 L7 L( y5 pblend/a1(11),chamfr,17.32233,pt(2)
* v% \# U0 d* e8 z) Oa1(12)=solsph/origin,x,y,z-5,diamtr,503 D/ Q+ }. G+ d. P9 A" N! _
a1(13)=subtra/a1(11),with,a1(12)7 p: h0 u; y7 n' _) h! I+ H2 V
a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009# Q- i7 d" ]! `. c0 I/ p' T
a1(15)=subtra/a1(13),with,a1(14)
/ {- U7 T* x# O# i" Z+ N/ Zpt(3)=point/x,y+49.9,z+10+ _* [/ G, s0 B( X5 t/ X
blend/a1(15),chamfr,0.5,pt(3)) R. L. s# x. E: K$ E
pt(4)=point/x,y+62.5,z
: S8 h/ V7 g/ X7 kblend/a1(15),chamfr,0.5,pt(4)* e* L( y% Q9 t9 y: g- U
pt(5)=point/x,y+62.5,z-158 E+ { R, q$ p
blend/a1(15),chamfr,0.5,pt(5)
4 ^$ q9 n& E: i0 Ept(6)=point/x,y+50,z-304 l# N2 d' k$ |* L! G, s7 W
blend/a1(15),chamfr,0.5,pt(6)
" K4 t; n8 z; Tpt(7)=point/x,y+35,z+10; W1 |) N& N. \$ ?
blend/a1(15),chamfr,0.5,pt(7)1 l: c/ a0 J# O6 R$ y
delete/pt(1..100)* o* O9 c9 s* Q$ p( y, ^
a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
: ^ U0 J( a) C, U _7 Q K$ X9 l3 ea1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-1) x% k9 P: q& \; O/ L
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1) [- `1 z" I' Z4 o4 @$ p
a1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-1
% X) \- I/ K! b7 ma1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
6 Q% R0 i, U3 R2 b& _" O$ f/ R" ya1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1) ^+ e+ ^& e, L* p
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1+ [2 T- m! x: D+ A' W0 w7 l
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1- X5 x, F. P/ P2 v1 ~& d& ^
a1(24)=subtra/a1(15),with,a1(16): M" m7 E% R: ~
a1(25)=subtra/a1(24),with,a1(17); M4 b, R) X- L! G0 b" E. ]& `# m a4 ^, g
a1(26)=subtra/a1(25),with,a1(18)( k/ a/ ?* H+ l
a1(27)=subtra/a1(26),with,a1(19)" I( c j/ t! r2 J4 r i
a1(28)=subtra/a1(27),with,a1(20)
: |! F+ }5 C$ r( Q. M; Xa1(29)=subtra/a1(28),with,a1(21): {: i1 P/ q" Q( k3 |
a1(30)=subtra/a1(29),with,a1(22): A4 `1 U3 v, K0 e6 M
a1(31)=subtra/a1(30),with,a1(23)5 ^* f2 t- J4 U# f. u
&color(a1(31))=121
/ t! N1 @& k' J& `. {" J O&name(a1(31))='JZ') T! J3 \! _4 E( l. _
7 y) y1 M* ]6 g$ T/ J, Q; Njump/l1:$ S0 W: h& ~* I; ^2 O
end:
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