悬赏10 G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!4 E h c4 w. o
2 n+ x( Q" z5 w3 B* l; V) ` 但现在的一个问题是怎样选择图形中已经有了的实体如图:6 I0 C& m% C; ~9 M" u( V
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/ y3 g1 k1 M. d/ \; X+ W' F- W% d 小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!
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1 `* x c0 V, t' Z( S 源代码:
( Y1 P, I! W; c/ n& v$ W1 f! h entity/a1(100),pt(100)+ P& j+ V5 V4 F, V p: d Q
; f& z) t9 v" c+ |; j l1:
( `6 L5 \+ E5 F gpos/'选择一个点',x,y,z,resp* D/ S" N# a# Z9 @9 g
jump/l1:,end:,,,resp
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param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp5 }/ B% N1 ]3 b* V7 ~& M0 y
jump/l10:,end:,,,resp/ b6 r% |1 a" b6 L: \' ]5 i, B
l2:
' ]6 e9 }6 M" j3 ~( r E6 \7 r a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1
% w) Z9 \8 P& K, s$ [) P/ B a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1' F+ M. Y( B% l+ N5 d
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-1/ Q8 }; ~' H+ ~9 O# U. X
a1(4)=unite/a1(1),with,a1(2)
0 W3 o: H; w% {: B6 E# y a1(5)=unite/a1(3),with,a1(4)8 ~ a7 L* B% g3 m& b
a1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-1
# X$ z, v1 |+ u, P i3 T: s; s a1(7)=unite/a1(5),with,a1(6)7 U, m! T/ G6 a. w# H0 n2 j
pt(1)=point/x+11.53,y,z-30. Q1 a9 Q( S7 W4 I
blend/a1(7),chamfr,14,pt(1)6 ]" `& w/ N2 O. K
a1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1( X6 p' F% ^' l2 F
a1(9)=unite/a1(7),with,a1(8)
' ~9 }4 }! w5 I: i2 B a1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,706 Q6 Y' w8 P& f' S
a1(11)=subtra/a1(9),with,a1(10)
; n0 t8 n+ @2 n( W8 g3 ] pt(2)=point/x+35,y,z-22.67767 w0 _, j* g3 o. T; N* O, B, J5 ?
blend/a1(11),chamfr,17.32233,pt(2)9 {: A: {( L G
a1(12)=solsph/origin,x,y,z-5,diamtr,50& `7 \1 L1 W9 e( a+ d6 }
a1(13)=subtra/a1(11),with,a1(12)+ n$ p4 c3 l% t8 g
a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009
) d2 C* y( n! x; X" I0 H a1(15)=subtra/a1(13),with,a1(14)8 F3 G$ x: l. n
pt(3)=point/x,y+49.9,z+10, X [ E# B0 t# z( \3 Q2 j! G7 G
blend/a1(15),chamfr,0.5,pt(3)
8 K" {: q/ d2 v# T9 M' i3 C+ d+ Z pt(4)=point/x,y+62.5,z
4 T6 s: e. [1 P% d' w blend/a1(15),chamfr,0.5,pt(4)
+ ^0 s8 S( X8 `, b G pt(5)=point/x,y+62.5,z-15
% x8 a. J8 Q# o5 N blend/a1(15),chamfr,0.5,pt(5)
& A$ v$ \( b0 a2 A5 h2 R1 ~ pt(6)=point/x,y+50,z-30& d. W" [ D% \3 e+ F5 H
blend/a1(15),chamfr,0.5,pt(6)
1 y6 ~- f7 x- z: u' M5 N- C# z$ t6 q+ X2 ^ pt(7)=point/x,y+35,z+10# t% Z2 d# l$ y8 @
blend/a1(15),chamfr,0.5,pt(7)
8 W" v# b* w$ U2 N+ B delete/pt(1..100)
/ x0 k. [* Z8 h' {4 \ a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1* b5 j, A1 e% h' B* D2 y
a1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-11 ~( T+ o6 o( ]! O9 M! k, c
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1+ T; z: }( }) s" w! J4 ]7 q
a1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-19 s/ k- ]: F; M+ N0 V
a1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1) s+ u O) J2 g, C
a1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-1+ D- N$ v- p3 i0 h
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-18 j* e7 G, E* U& E2 z5 [) U& b8 Y9 x
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
' n0 k8 g- O6 E' T' \/ w a1(24)=subtra/a1(15),with,a1(16)
& y; e0 }4 S' w" e9 W$ W a1(25)=subtra/a1(24),with,a1(17): C" \$ T1 x& T
a1(26)=subtra/a1(25),with,a1(18)
, x% H# L4 A* J2 @ a1(27)=subtra/a1(26),with,a1(19)
! U. j7 L: Q. i0 ?6 z8 x a1(28)=subtra/a1(27),with,a1(20)
" G/ @& s" q, n: i( u/ P5 Y6 i% T& P a1(29)=subtra/a1(28),with,a1(21)( b$ w6 W7 [ n, m: O0 E! _
a1(30)=subtra/a1(29),with,a1(22)) L" W H- s' [) F" E# `+ M
a1(31)=subtra/a1(30),with,a1(23)5 j J1 U1 M9 H1 T" v5 S
&color(a1(31))=1213 c3 c3 t3 p% k
&name(a1(31))='JZ'8 [1 f# z8 a. B6 D! K- }
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jump/l1:0 J, [! I$ ~/ C$ T k
end:8 K% M9 Y) V q. \+ R2 Z
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