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悬赏10G币未解决
昨天写了个唧嘴的程序,但是不理想,我想要是能想HB大哥外挂那样可以调用后自动和相关的地方进行布尔运算就好了!
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但现在的一个问题是怎样选择图形中已经有了的实体如图:4 D) E5 Y6 W- a9 C& u- \6 h
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小弟是刚刚学GIRP的,希望能用高手大哥指点!谢!7 e2 H* h6 ^: K$ U0 s
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9 ?0 g) N4 Z6 E源代码:
- J/ h* k9 `! L% k/ w- hentity/a1(100),pt(100)6 [3 [2 R U W, _$ l
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l1:
- x/ T& l2 W8 @7 a5 q3 g# Z8 C gpos/'选择一个点',x,y,z,resp4 v7 t9 @! [. ^- Z! q8 ]
jump/l1:,end:,,,resp
: W7 ?8 N) s, G/ s' r% Vl10:
9 ?4 m/ ?+ {. h _: d param/'请输入坐标值','XC',x,'YC',y,'ZC',z,resp6 O4 o' h6 [$ p7 n3 B2 [& K
jump/l10:,end:,,,resp
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a1(1)=solcyl/origin,x,y,z,height,10,diamtr,99.8,axis,0,0,1) L- l4 R8 v0 x1 e* H! j( B
a1(2)=solcyl/origin,x,y,z,height,15,diamtr,125,axis,0,0,-1( [! c- W* H& K( m: r( M
a1(3)=solcyl/origin,x,y,z,height,30,diamtr,100,axis,0,0,-1
1 O8 i4 q* L( O2 aa1(4)=unite/a1(1),with,a1(2)0 o3 z! e' D, F( A2 |
a1(5)=unite/a1(3),with,a1(4)9 ^2 v! Y& }) r, @1 B
a1(6)=solcon/origin,x,y,z-30,height,20,diamtr,23.053079,16,axis,0,0,-1
E/ t2 ?' x6 y2 x9 b% v: ra1(7)=unite/a1(5),with,a1(6)
: Y2 J! Q7 H6 U# C8 T1 lpt(1)=point/x+11.53,y,z-300 ^0 B) |8 L5 D
blend/a1(7),chamfr,14,pt(1)
Z8 O: _0 l. M$ M Y' Ua1(8)=solcon/origin,x,y,z-51.5,height,1.5,diamtr,13,12.471019,axis,0,0,1$ j+ S# {$ [# e# ~6 [/ @
a1(9)=unite/a1(7),with,a1(8)
5 _' S- \ T! k5 U* sa1(10)=solcyl/origin,x,y,z-22.67767,height,50,diamtr,70
5 \% j" \8 b4 e5 Na1(11)=subtra/a1(9),with,a1(10)
/ X6 ~: n3 U( l0 w1 Y/ _- M; Hpt(2)=point/x+35,y,z-22.67767% U* l# _; h% x8 k; U0 {5 p" p
blend/a1(11),chamfr,17.32233,pt(2)0 C6 S3 q( d' _ W
a1(12)=solsph/origin,x,y,z-5,diamtr,508 L9 i8 @2 }9 b: W, z- E( G* X0 l
a1(13)=subtra/a1(11),with,a1(12). T- v1 M: F: G, }8 Y1 V; o
a1(14)=solcon/origin,x,y,z-17.68,height,-40,diamtr,2,6.893009
: t% G e7 w6 h. e- s K, Oa1(15)=subtra/a1(13),with,a1(14)
+ z6 a. p6 `: R$ y8 kpt(3)=point/x,y+49.9,z+10
4 J3 k( i* G8 Gblend/a1(15),chamfr,0.5,pt(3)! r( S2 F6 F# C
pt(4)=point/x,y+62.5,z' [+ u9 l) P6 N6 ]* P
blend/a1(15),chamfr,0.5,pt(4)3 X8 n+ n& [% n* F/ l$ b$ i
pt(5)=point/x,y+62.5,z-15
# Y! }# G& A( Q1 K7 }blend/a1(15),chamfr,0.5,pt(5)7 t9 s" e7 I M3 q% j% F
pt(6)=point/x,y+50,z-30/ h t0 J4 K/ X- f7 @
blend/a1(15),chamfr,0.5,pt(6)! ^$ _$ y4 M O, R. r2 V) `
pt(7)=point/x,y+35,z+10
3 }2 W6 P0 W' y9 Bblend/a1(15),chamfr,0.5,pt(7)2 h" r7 C% C. M; Z
delete/pt(1..100)% v8 b' u" X7 q* \; j$ R
a1(16)=solcyl/origin,x,y+56.5,z,height,6,diamtr,10,axis,0,0,-1
- l- i% f9 ^' J. n' B1 h6 Ya1(17)=solcyl/origin,x,y-56.5,z,height,6,diamtr,10,axis,0,0,-19 C& I5 A" w( \0 ^
a1(18)=solcyl/origin,x-56.5,y,z,height,6,diamtr,10,axis,0,0,-1
0 m& b9 j3 k5 @- p0 ~% ]+ ba1(19)=solcyl/origin,x+56.5,y,z,height,6,diamtr,10,axis,0,0,-1
$ F+ [+ V9 w) X$ p' R8 Ea1(20)=solcyl/origin,x,y+56.5,z,height,15,diamtr,5.5,axis,0,0,-1
: y ^. l# n( q# U: X2 Q- f; [a1(21)=solcyl/origin,x,y-56.5,z,height,15,diamtr,5.5,axis,0,0,-14 c0 `, q2 o5 h; |
a1(22)=solcyl/origin,x-56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1, g8 f g& i1 R- P) [' [, u
a1(23)=solcyl/origin,x+56.5,y,z,height,15,diamtr,5.5,axis,0,0,-1
( z/ f& ^' k8 L- Q& M. La1(24)=subtra/a1(15),with,a1(16)! Y* h7 S/ |0 a3 ?/ T) S
a1(25)=subtra/a1(24),with,a1(17)
3 j/ `/ A: e; @# p/ ]a1(26)=subtra/a1(25),with,a1(18)
3 B+ D6 C: d" fa1(27)=subtra/a1(26),with,a1(19)
2 G; J6 \0 \: ] k3 A# X; Y% na1(28)=subtra/a1(27),with,a1(20)
7 }! \' n& k/ F i$ e# S5 Q) m: Qa1(29)=subtra/a1(28),with,a1(21)
- D# b* V" j: p$ C$ U: {8 a6 fa1(30)=subtra/a1(29),with,a1(22), L1 ^: S& X8 w; E
a1(31)=subtra/a1(30),with,a1(23)
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&name(a1(31))='JZ'
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jump/l1:4 `- s% P3 d8 ` J8 H
end:
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