整套的3d輪胎grip程式

dd007ok

那里有整套的3d輪胎grip程式？

ruju

entity/pt(100),ln(100),cr(100),obj1(100),obj2(100),ent(100)
( L4 D& Y$ r0 b! o  ?. u5 y* enumber/nd,ndi,nr,k,wd,wr,mat1(12),mat2(12),mat3(12),mat4(12),mat5(12)
data/ndi,23,k,250
7 A( o1 e. G! C+ s* t) Yln(1)=line/0,-100,0,100
mat1=matrix/mirror,ln(1)
$$---------------------轮胎--------------------$$
$$输入轮胎相应尺寸参数
back:
param/'输入参数','轮辋直径(in)',ndi,'轮胎宽度(mm)',k,rsp
  E" l3 n: {: \9 Q4 D, ~jump/back:,cancel:,ok:,rsp
# z7 D+ x8 C% @ok:
+ [7 n- \  ^; b! s# ^6 f" ~$$判断参数正误
& v9 z5 W  K0 G8 k( A6 b0 C5 O5 d' `ifthen/ndi<14 or ndi>25
messg/'轮辋直径超出范围(14-25)，请重新输入'
4 o8 {6 U, D; J. [2 Wjump/back:
" O3 H% u# ?2 T3 K5 G" p9 f" R8 telse
& g8 [! T5 t! `* ejump/l1:
endif
l1:
ifthen/k<150 or k>350
0 `* w  k" B' A  i% Qmessg/'轮胎宽度超出范围(150-350)，请重新输入'
6 g* F+ M$ K& X! n2 d% E3 Hjump/back:
else
jump/l2:
# D* s5 Q* g' r) S; Bendif
l2:
. V; K0 d1 @' c# ond=ndi*1000/36
4 j9 H; `8 S+ O+ ?2 e. e: E% e8 K* Xwd=1.5*nd
nr=nd/2
wr=wd/2
$$生成半轮胎周向截面点、线
4 k" W  R/ R- q  k7 ypt(1)=point/(-k/2*0.93),(0.98*wr)
pt(2)=point/(-k/4),(0.99*wr)
pt(3)=point/0,wr
pt(4)=point/(-k/2),(wr+nr)/2
- q- h8 [6 C0 K  xpt(5)=point/(-k/2*0.93),nr
& L$ ]; Q  ]2 T/ Opt(6)=point/pt(5),delta,(k/30),(-0.1*nr),0
pt(7)=point/0,0.9*nr
pt(8)=point/pt(1),delta,5,-5,0
9 |+ J* J7 Y# Cpt(9)=point/pt(6),delta,5,5,0
8 P6 p& @/ g* L$ {8 O5 V$ A8 K! hpt(10)=point/pt(5),delta,5,0,0
: X7 g* o- P( u7 l3 C  z5 T# {: Wcr(1)=circle/pt(3),pt(2),pt(1)
cr(2)=circle/pt(1),pt(4),pt(5)
6 T: O" M/ _5 m/ ?2 q; N( f' s/ jln(2)=line/pt(5),pt(6)
( }' Q8 S# n4 v) ]* Mln(3)=line/pt(6),pt(7)
ln(4)=line/pt(7),pt(3)
: h7 `7 f% U$ ?2 u4 z& o# O$$倒角处理
obj1(1)=fillet/cr(1),cr(2),center,pt(8),radius,15
* x/ E& ?+ ]  j* xobj1(2)=fillet/cr(2),ln(2),center,pt(10),radius,15
) C' F2 K% x% vobj1(3)=fillet/ln(2),ln(3),center,pt(9),radius,15
$$旋转
ent(1)=solrev/cr(1..2),ln(2..4),obj1(1..3),origin,0,0,0,atangl,360,axis,1,0,0
, S1 S5 O- p8 q" F- Q$$花纹线
1 b3 m8 N# L; G! E1 L9 h( g, Fln(5)=line/-k/2,k/8,wr+10,-k/4,k/8,wr+10
8 ?. z2 s0 [% G5 jln(6)=line/-k/4,k/8,wr+10,-k/6,0,wr+10
1 ^" @/ Y3 }. {2 nln(7)=line/-k/2,k/8,wr+10,-k/2,k/4,wr+10
: S5 C' \! m& k: |% J  o5 Mln(8)=line/-k/2,k/4,wr+10,-k/5,k/4,wr+10
ln(9)=line/-k/5,k/4,wr+10,-k/24,0,wr+10
ln(10)=line/-k/24,0,wr+10,-k/6,0,wr+10
, H9 Q' G2 \, ]/ q2 k0 j6 y$$切花纹
# q6 D8 l3 {& J9 o6 J  v: C  }mat2=matrix/mirror,ln(10)
obj1(5)=solext/ln(5..10),height,10+wr/30,axis,0,0,-1
, H4 ^- R) @0 ?: w/ {obj1(6)=transf/mat2,obj1(5)
5 `( l, a. x3 d# x4 r- aobj1(7)=unite/obj1(5),with,obj1(6)
i=intf(3.1415926*wd/(3*k/8))
# i7 w2 \- _' ?% c2 Rn=1
j=8
xh1:
/ }  Y+ U8 Z& U8 Q( K  S/ ^  pifthen/n<=i-1
. Y. f: m3 p' \4 ]: g3 Imat3=matrix/yzrot,n*(360/i)
2 Z, {5 g- Y, q7 ^/ jobj1(j)=transf/mat3,obj1(7)
j=j+1
n=n+1
, z  x; z# M$ p4 u6 b& ?jump/xh1:
9 J  a" G5 @8 |endif
7 H2 E7 Y) E$ c* oent(2)=subtra/ent(1),with,obj1(7..j-1)
& ^1 a& Y2 S5 f4 E5 Dent(3)=transf/mat1,ent(2)
mat4=matrix/yzrot,360/i/2
6 t6 O3 Q& |4 o4 k4 ^! xent(4)=transf/mat4,ent(3),move
ent(5)=unite/ent(2),with,ent(4)
&color(ent(5))=&gray
$$----------------------轮毂--------------------$$
$$轮毂截面点、线
pt(11)=transf/mat1,pt(6)
pt(12)=point/pt(6),delta,0,-wd/40,0
$ g: W2 u" _. j- a. m0 Wpt(13)=transf/mat1,pt(12)
# M  l7 g+ D: ]pt(14)=point/pt(7),delta,0,-wd/40*2,0
ln(11)=line/pt(11),pt(6)
ln(12)=line/pt(6),pt(12)
ln(13)=line/pt(11),pt(13)
2 {4 X! @& W4 zcr(3)=circle/pt(12),pt(14),pt(13)
pt(15)=point/pt(14),delta,-k/5,wd/30,0
( \6 x7 t, H2 Y$ N9 Y. E7 U& Z3 cpt(16)=point/pt(15),delta,-k/10,0,0
0 N. m+ N. M4 j. V) r7 E) Mln(14)=line/pt(15),pt(16)
: \; R- ^, s7 C+ c0 f, H6 bpt(17)=point/pt(15),delta,-k/30,-0.2*nr,0
2 G  r3 f, A, Q8 Ppt(18)=point/pt(17),delta,-k/15,-0.2*nr,0
- O8 }% m$ w! d6 H: S$ z* Dpt(19)=point/pt(18),delta,-k/10,-0.2*nr,0
pt(20)=point/-0.4*k,0
7 Y7 K! G* P$ u: @* s' Rpt(21)=point/pt(17),delta,-k/10,0,0
pt(22)=point/pt(18),delta,-k/10,0,0
$ Y# {  r  \5 ~pt(23)=point/pt(19),delta,-k/10,0,0
pt(24)=point/-0.5*k,0
cr(4)=circle/pt(18),pt(17),pt(15)
cr(5)=circle/pt(18),pt(19),pt(20)
cr(6)=circle/pt(22),pt(21),pt(16)
, o- d3 V$ M( Z+ e4 Jcr(7)=circle/pt(22),pt(23),pt(24)
! t" A4 F. C) |* mln(15)=line/pt(20),pt(24)
$$旋转、倒棱
ent(6)=solrev/ln(11..13),cr(3),origin,0,0,0,atangl,360,axis,1,0,0
: V+ ^  \) r0 t( u! n. k+ L& Sblend/ent(6),radius,10
ent(7)=solrev/ln(14..15),cr(4..7),origin,0,0,0,atangl,360,axis,1,0,0
ent(8)=unite/ent(6),with,ent(7)
&color(ent(8))=&white
$$修型
obj2(1)=solcyl/origin,-k,0,0,height,k*2,diamtr,0.3*nr,axis,1,0,0
5 b; K+ I6 O7 nent(9)=subtra/ent(8),with,obj2(1)
0 @+ d2 Z- Q. \7 N# e' Bobj2(2)=solcyl/origin,-k,0.6*nr,0,height,2*k,diamtr,0.2*nr,axis,1,0,0
m=intf(3.1415926*nr/(0.4*nr))
g=1
8 s) r# `2 {1 Z3 Ow=3
xh2:
ifthen/g<=m-1
mat5=matrix/yzrot,g*(360/m)
- }1 P4 ?4 e! F* I& E, {, oobj2(w)=transf/mat5,obj2(2)
w=w+1
, q! D) D) D+ M: s  X. |g=g+1
1 s" n% P. ]' L8 ?jump/xh2:
endif
ent(10)=subtra/ent(9),with,obj2(2..w-1)
" S3 A# j# j5 q( V) T$$消隐辅助点、线
blank/pt(1..24),cr(1..7),ln(1..15),obj1(1..3)
, q7 r! N1 Y9 W6 _cancel:
# w$ |/ r4 _1 I. vhalt

longlonglm

额 这。。。怎么没有人发表一下观点啊

longlonglm

试过了程序完全正确 如果能自己写出来 估计GRIP 学的就差不多了吧

davidcad

感謝分享,努力學習