整套的3d輪胎grip程式

dd007ok

那里有整套的3d輪胎grip程式？

ruju

entity/pt(100),ln(100),cr(100),obj1(100),obj2(100),ent(100)
( w$ \7 t5 R) y* X9 _number/nd,ndi,nr,k,wd,wr,mat1(12),mat2(12),mat3(12),mat4(12),mat5(12)
data/ndi,23,k,250
ln(1)=line/0,-100,0,100
1 U6 O4 u( z: ~mat1=matrix/mirror,ln(1)
( D, f' t8 i1 `5 l$$---------------------轮胎--------------------$$
$$输入轮胎相应尺寸参数
back:
param/'输入参数','轮辋直径(in)',ndi,'轮胎宽度(mm)',k,rsp
2 }! ~7 L7 w2 m- b' x8 tjump/back:,cancel:,ok:,rsp
ok:
0 x; l2 D9 N2 S, s9 S9 T$$判断参数正误
ifthen/ndi<14 or ndi>25
messg/'轮辋直径超出范围(14-25)，请重新输入'
: ~& t& T1 y1 `  S1 l- t: pjump/back:
0 }3 z* J3 l& E7 G; ^4 A: Jelse
7 u3 ^* Q4 y! W# Y  {, w( P" Bjump/l1:
endif
1 f" ~7 s1 d4 p, H" x) Ql1:
' K5 S: L" G4 e; e* Mifthen/k<150 or k>350
messg/'轮胎宽度超出范围(150-350)，请重新输入'
jump/back:
& |! ^) Z! z% X& Yelse
1 E! K9 x+ N7 e  |. g5 o6 ?jump/l2:
endif
l2:
, }7 E. \# Y! z8 O. `- pnd=ndi*1000/36
6 N* I# d" A$ D3 S; Vwd=1.5*nd
nr=nd/2
wr=wd/2
: o+ K  t" }% C$$生成半轮胎周向截面点、线
pt(1)=point/(-k/2*0.93),(0.98*wr)
5 Q# t. s0 F: l% t  ~pt(2)=point/(-k/4),(0.99*wr)
2 F/ G# H4 A4 Y! A( x6 z6 N. E  Mpt(3)=point/0,wr
pt(4)=point/(-k/2),(wr+nr)/2
pt(5)=point/(-k/2*0.93),nr
pt(6)=point/pt(5),delta,(k/30),(-0.1*nr),0
" G( m! n; v  \4 c$ `( k; fpt(7)=point/0,0.9*nr
pt(8)=point/pt(1),delta,5,-5,0
pt(9)=point/pt(6),delta,5,5,0
pt(10)=point/pt(5),delta,5,0,0
cr(1)=circle/pt(3),pt(2),pt(1)
( J+ i1 `4 }. _$ t1 ?" Hcr(2)=circle/pt(1),pt(4),pt(5)
9 [& B- u4 w; m; d6 mln(2)=line/pt(5),pt(6)
: S& {( V; ?" m! h+ W2 X2 qln(3)=line/pt(6),pt(7)
6 s' ~0 O3 h1 o) \) S) }ln(4)=line/pt(7),pt(3)
$$倒角处理
' t- ~/ y9 c# |; j* E/ A4 }obj1(1)=fillet/cr(1),cr(2),center,pt(8),radius,15
obj1(2)=fillet/cr(2),ln(2),center,pt(10),radius,15
5 B% i. N9 Z/ p( Tobj1(3)=fillet/ln(2),ln(3),center,pt(9),radius,15
$$旋转
ent(1)=solrev/cr(1..2),ln(2..4),obj1(1..3),origin,0,0,0,atangl,360,axis,1,0,0
5 |5 L& K4 v0 y/ O! ]! |8 P$$花纹线
ln(5)=line/-k/2,k/8,wr+10,-k/4,k/8,wr+10
ln(6)=line/-k/4,k/8,wr+10,-k/6,0,wr+10
) R  J6 y5 d7 e' S/ p1 Kln(7)=line/-k/2,k/8,wr+10,-k/2,k/4,wr+10
ln(8)=line/-k/2,k/4,wr+10,-k/5,k/4,wr+10
ln(9)=line/-k/5,k/4,wr+10,-k/24,0,wr+10
ln(10)=line/-k/24,0,wr+10,-k/6,0,wr+10
+ [& N" M" F4 i$ R( u' v2 l$$切花纹
' @  p( z6 s$ c& Y9 f9 w- Y+ Cmat2=matrix/mirror,ln(10)
: N6 }2 P; p, h9 {8 gobj1(5)=solext/ln(5..10),height,10+wr/30,axis,0,0,-1
+ D6 Q! N) B6 a7 e. T, S) t" Uobj1(6)=transf/mat2,obj1(5)
obj1(7)=unite/obj1(5),with,obj1(6)
4 T: j6 |3 _3 Wi=intf(3.1415926*wd/(3*k/8))
) L: Q3 _% R, W: W9 `n=1
j=8
" m- ^  V+ g' ]xh1:
1 z9 }7 t2 n* c& y/ S& tifthen/n<=i-1
& b( m) X1 s+ Y' Q: J" J% N8 Pmat3=matrix/yzrot,n*(360/i)
obj1(j)=transf/mat3,obj1(7)
j=j+1
3 e; e: i' j) ~/ o- z  F7 r$ Rn=n+1
jump/xh1:
* F# V* C+ j! j& r5 i2 T  Cendif
ent(2)=subtra/ent(1),with,obj1(7..j-1)
ent(3)=transf/mat1,ent(2)
mat4=matrix/yzrot,360/i/2
ent(4)=transf/mat4,ent(3),move
. _# a) E; t; ~ent(5)=unite/ent(2),with,ent(4)
&color(ent(5))=&gray
% r; A' ~3 [# \. N$$----------------------轮毂--------------------$$
7 q: y2 n/ M" j# U$$轮毂截面点、线
8 h; B$ R3 ^3 ?pt(11)=transf/mat1,pt(6)
pt(12)=point/pt(6),delta,0,-wd/40,0
pt(13)=transf/mat1,pt(12)
pt(14)=point/pt(7),delta,0,-wd/40*2,0
ln(11)=line/pt(11),pt(6)
ln(12)=line/pt(6),pt(12)
ln(13)=line/pt(11),pt(13)
+ F, Y. D, e/ U2 F" b2 k2 Ecr(3)=circle/pt(12),pt(14),pt(13)
pt(15)=point/pt(14),delta,-k/5,wd/30,0
pt(16)=point/pt(15),delta,-k/10,0,0
" N% L" ?/ P  P) n; xln(14)=line/pt(15),pt(16)
: |/ i3 a) v# d9 kpt(17)=point/pt(15),delta,-k/30,-0.2*nr,0
8 d8 j2 `# [9 ^! Ept(18)=point/pt(17),delta,-k/15,-0.2*nr,0
; c* R5 p5 o# I) {. [+ d$ P1 Opt(19)=point/pt(18),delta,-k/10,-0.2*nr,0
8 _. v; j, [. Q8 Gpt(20)=point/-0.4*k,0
* Y; @3 C0 ^% \( D9 Zpt(21)=point/pt(17),delta,-k/10,0,0
2 z2 \& L& H+ v& `  [6 h% Rpt(22)=point/pt(18),delta,-k/10,0,0
pt(23)=point/pt(19),delta,-k/10,0,0
pt(24)=point/-0.5*k,0
: O) x8 T( n# C7 g6 p, [cr(4)=circle/pt(18),pt(17),pt(15)
cr(5)=circle/pt(18),pt(19),pt(20)
# C" Y$ ]* ?( c+ pcr(6)=circle/pt(22),pt(21),pt(16)
cr(7)=circle/pt(22),pt(23),pt(24)
* y; F7 M+ `, X! jln(15)=line/pt(20),pt(24)
$$旋转、倒棱
: @0 ^+ Z2 i$ m1 }9 Qent(6)=solrev/ln(11..13),cr(3),origin,0,0,0,atangl,360,axis,1,0,0
+ S( m; Q& {# mblend/ent(6),radius,10
ent(7)=solrev/ln(14..15),cr(4..7),origin,0,0,0,atangl,360,axis,1,0,0
; z0 ?( e# D( N6 D" D9 {ent(8)=unite/ent(6),with,ent(7)
&color(ent(8))=&white
' Q, u$ M) @/ }$ v1 H$$修型
obj2(1)=solcyl/origin,-k,0,0,height,k*2,diamtr,0.3*nr,axis,1,0,0
ent(9)=subtra/ent(8),with,obj2(1)
3 U+ T* k( Z' ]% B; P% Aobj2(2)=solcyl/origin,-k,0.6*nr,0,height,2*k,diamtr,0.2*nr,axis,1,0,0
m=intf(3.1415926*nr/(0.4*nr))
9 q( D2 l. ], e' [5 P4 ]5 `6 w2 }g=1
: }. O  \' W  _4 |w=3
xh2:
ifthen/g<=m-1
/ D' u* q- ?4 N# l( \$ |- amat5=matrix/yzrot,g*(360/m)
9 Z1 v/ j; s7 z6 G, uobj2(w)=transf/mat5,obj2(2)
5 m. ~5 ]* a8 y) I; z: E7 Ww=w+1
! H8 {4 b+ g7 w! b& Q7 m4 U/ {g=g+1
jump/xh2:
endif
8 l1 m3 V4 \- v9 D+ C" Z: tent(10)=subtra/ent(9),with,obj2(2..w-1)
$$消隐辅助点、线
- e2 e3 Y6 k6 y3 a, E9 rblank/pt(1..24),cr(1..7),ln(1..15),obj1(1..3)
cancel:
+ K2 i0 T/ c. s) v$ N- Y  hhalt

longlonglm

额 这。。。怎么没有人发表一下观点啊

longlonglm

试过了程序完全正确 如果能自己写出来 估计GRIP 学的就差不多了吧

davidcad

感謝分享,努力學習