整套的3d輪胎grip程式

dd007ok

那里有整套的3d輪胎grip程式？

ruju

entity/pt(100),ln(100),cr(100),obj1(100),obj2(100),ent(100)
number/nd,ndi,nr,k,wd,wr,mat1(12),mat2(12),mat3(12),mat4(12),mat5(12)
data/ndi,23,k,250
ln(1)=line/0,-100,0,100
mat1=matrix/mirror,ln(1)
' e# b4 ~7 l- T& y3 V8 Q7 R$$---------------------轮胎--------------------$$
$$输入轮胎相应尺寸参数
back:
" O2 s6 l8 I2 o8 R. Dparam/'输入参数','轮辋直径(in)',ndi,'轮胎宽度(mm)',k,rsp
  F: Z2 p" r0 ~5 V+ bjump/back:,cancel:,ok:,rsp
, f' `# V, @/ _& K8 s: v0 p0 aok:
5 S  o" B  N6 V1 w. b2 L# H8 B$$判断参数正误
ifthen/ndi<14 or ndi>25
messg/'轮辋直径超出范围(14-25)，请重新输入'
2 b+ L! W% `* f+ J& a4 Qjump/back:
% _7 u- I5 @: ^5 S' Telse
' l3 [5 W" I5 Cjump/l1:
0 O0 u/ e+ J) M$ A* A* Cendif
/ V# p3 J! _* s& z' |8 L* j3 sl1:
7 S# l! Q5 Y( }3 Jifthen/k<150 or k>350
+ M) A  j  p/ g3 pmessg/'轮胎宽度超出范围(150-350)，请重新输入'
8 [- ]5 z4 B) P* z5 {' g1 I/ a: Jjump/back:
else
jump/l2:
endif
8 @6 ~8 @# x% f3 L: Z. |1 N3 x1 xl2:
  t6 R9 u, \# \9 _" |6 end=ndi*1000/36
wd=1.5*nd
nr=nd/2
( Z0 u1 w! f6 `9 R. k- X* }wr=wd/2
( b( b( J+ S8 D' T$$生成半轮胎周向截面点、线
; R) @- X- w- Tpt(1)=point/(-k/2*0.93),(0.98*wr)
pt(2)=point/(-k/4),(0.99*wr)
pt(3)=point/0,wr
- K. Y/ ]4 v0 I3 j. x4 n# k2 {8 \, Ypt(4)=point/(-k/2),(wr+nr)/2
3 c1 K% ^* S5 Zpt(5)=point/(-k/2*0.93),nr
pt(6)=point/pt(5),delta,(k/30),(-0.1*nr),0
pt(7)=point/0,0.9*nr
* {+ q$ d4 f6 q/ h* tpt(8)=point/pt(1),delta,5,-5,0
$ L4 j$ [9 ?  l) D, {3 U1 H0 k) upt(9)=point/pt(6),delta,5,5,0
0 N, I: G% a5 G, {& d8 b3 G6 ppt(10)=point/pt(5),delta,5,0,0
* O4 X; z2 q2 P. n0 g2 \cr(1)=circle/pt(3),pt(2),pt(1)
cr(2)=circle/pt(1),pt(4),pt(5)
; ]" D1 e, q" M) U% `2 X1 nln(2)=line/pt(5),pt(6)
ln(3)=line/pt(6),pt(7)
- g3 f" ~4 o* g: i2 b+ x  f6 i& eln(4)=line/pt(7),pt(3)
% b4 B, O. ?- z' Z$$倒角处理
obj1(1)=fillet/cr(1),cr(2),center,pt(8),radius,15
obj1(2)=fillet/cr(2),ln(2),center,pt(10),radius,15
obj1(3)=fillet/ln(2),ln(3),center,pt(9),radius,15
$$旋转
- n% n' j. \% xent(1)=solrev/cr(1..2),ln(2..4),obj1(1..3),origin,0,0,0,atangl,360,axis,1,0,0
$$花纹线
ln(5)=line/-k/2,k/8,wr+10,-k/4,k/8,wr+10
ln(6)=line/-k/4,k/8,wr+10,-k/6,0,wr+10
ln(7)=line/-k/2,k/8,wr+10,-k/2,k/4,wr+10
) t. |$ Q5 Z, G( T) Qln(8)=line/-k/2,k/4,wr+10,-k/5,k/4,wr+10
* B3 \/ ~2 ?; h$ f, hln(9)=line/-k/5,k/4,wr+10,-k/24,0,wr+10
4 Z! `2 F+ M% d  z6 R9 n2 ]2 Q* Uln(10)=line/-k/24,0,wr+10,-k/6,0,wr+10
) Q" f+ z% m, [7 B* I; R$$切花纹
8 q0 h& {4 l) L7 omat2=matrix/mirror,ln(10)
! k. ]' P- w, O( g$ F+ g4 _obj1(5)=solext/ln(5..10),height,10+wr/30,axis,0,0,-1
obj1(6)=transf/mat2,obj1(5)
obj1(7)=unite/obj1(5),with,obj1(6)
i=intf(3.1415926*wd/(3*k/8))
; S& D0 @! t8 X+ Yn=1
j=8
3 K$ b9 k; `' |) o" U, Q0 {; lxh1:
! M6 X6 ], G0 K7 K% wifthen/n<=i-1
mat3=matrix/yzrot,n*(360/i)
obj1(j)=transf/mat3,obj1(7)
j=j+1
n=n+1
jump/xh1:
4 t5 E. G9 A1 t- x* V7 n- tendif
) b( O4 W; w0 oent(2)=subtra/ent(1),with,obj1(7..j-1)
ent(3)=transf/mat1,ent(2)
' k) J1 K# H9 a, Imat4=matrix/yzrot,360/i/2
ent(4)=transf/mat4,ent(3),move
% w, f. F3 n+ P6 J2 Gent(5)=unite/ent(2),with,ent(4)
/ c/ S: P- C* X; Q&color(ent(5))=&gray
$$----------------------轮毂--------------------$$
$$轮毂截面点、线
pt(11)=transf/mat1,pt(6)
pt(12)=point/pt(6),delta,0,-wd/40,0
5 n& y0 m4 W* ]$ l5 `& L- jpt(13)=transf/mat1,pt(12)
0 O) t4 l# H8 T2 D7 qpt(14)=point/pt(7),delta,0,-wd/40*2,0
ln(11)=line/pt(11),pt(6)
ln(12)=line/pt(6),pt(12)
- b, c" ]- z8 O# F% Lln(13)=line/pt(11),pt(13)
cr(3)=circle/pt(12),pt(14),pt(13)
pt(15)=point/pt(14),delta,-k/5,wd/30,0
pt(16)=point/pt(15),delta,-k/10,0,0
7 ]$ O2 C0 M, \1 d! K9 Vln(14)=line/pt(15),pt(16)
pt(17)=point/pt(15),delta,-k/30,-0.2*nr,0
! C, p& f/ G- e4 n4 X! C. a6 W; F% rpt(18)=point/pt(17),delta,-k/15,-0.2*nr,0
1 {0 J2 o: S# Tpt(19)=point/pt(18),delta,-k/10,-0.2*nr,0
pt(20)=point/-0.4*k,0
+ W+ v0 X$ V) W8 Ypt(21)=point/pt(17),delta,-k/10,0,0
pt(22)=point/pt(18),delta,-k/10,0,0
* v, V( s0 O; Upt(23)=point/pt(19),delta,-k/10,0,0
pt(24)=point/-0.5*k,0
+ X7 s) m6 N- ]' G% D, Zcr(4)=circle/pt(18),pt(17),pt(15)
cr(5)=circle/pt(18),pt(19),pt(20)
. z' G3 Z3 M9 E- ycr(6)=circle/pt(22),pt(21),pt(16)
cr(7)=circle/pt(22),pt(23),pt(24)
6 j0 y; |0 d/ k$ w$ E% c$ Hln(15)=line/pt(20),pt(24)
6 \6 N0 Z( h  E# E$ z: X! J0 J$$旋转、倒棱
+ @/ ~+ j+ k" Z; }8 A7 pent(6)=solrev/ln(11..13),cr(3),origin,0,0,0,atangl,360,axis,1,0,0
blend/ent(6),radius,10
ent(7)=solrev/ln(14..15),cr(4..7),origin,0,0,0,atangl,360,axis,1,0,0
ent(8)=unite/ent(6),with,ent(7)
&color(ent(8))=&white
$$修型
obj2(1)=solcyl/origin,-k,0,0,height,k*2,diamtr,0.3*nr,axis,1,0,0
ent(9)=subtra/ent(8),with,obj2(1)
obj2(2)=solcyl/origin,-k,0.6*nr,0,height,2*k,diamtr,0.2*nr,axis,1,0,0
m=intf(3.1415926*nr/(0.4*nr))
' S. t; Y1 Q/ W( t8 B2 Rg=1
1 U8 v3 P) q0 l6 g& Q+ u4 qw=3
xh2:
" R1 r4 T) I) [0 p: A: h  Uifthen/g<=m-1
mat5=matrix/yzrot,g*(360/m)
+ b, ^1 I7 s7 gobj2(w)=transf/mat5,obj2(2)
w=w+1
' Z. t0 @9 v% K/ z6 s. mg=g+1
9 A7 w0 {- p; i, c/ i* rjump/xh2:
# \4 D0 ^! e/ H9 U7 H& _endif
& C# V% u! {  C& g' E9 e2 x8 B2 aent(10)=subtra/ent(9),with,obj2(2..w-1)
% f( i3 j- Y# O$$消隐辅助点、线
6 s, I" ^% b2 u& hblank/pt(1..24),cr(1..7),ln(1..15),obj1(1..3)
/ l6 \; v! N1 }& Y/ }cancel:
halt

longlonglm

额 这。。。怎么没有人发表一下观点啊

longlonglm

试过了程序完全正确 如果能自己写出来 估计GRIP 学的就差不多了吧

davidcad

感謝分享,努力學習