整套的3d輪胎grip程式

dd007ok

那里有整套的3d輪胎grip程式？

ruju

entity/pt(100),ln(100),cr(100),obj1(100),obj2(100),ent(100)
number/nd,ndi,nr,k,wd,wr,mat1(12),mat2(12),mat3(12),mat4(12),mat5(12)
data/ndi,23,k,250
ln(1)=line/0,-100,0,100
2 u2 t, y& j. C# ]9 `mat1=matrix/mirror,ln(1)
$$---------------------轮胎--------------------$$
$$输入轮胎相应尺寸参数
back:
/ f: P: c6 N2 Y; |  D9 cparam/'输入参数','轮辋直径(in)',ndi,'轮胎宽度(mm)',k,rsp
jump/back:,cancel:,ok:,rsp
- _6 P; w% T* L( \ok:
9 j/ V/ z- ^+ w+ Q' E$$判断参数正误
ifthen/ndi<14 or ndi>25
messg/'轮辋直径超出范围(14-25)，请重新输入'
8 c/ F5 m+ Z8 U! A( V1 C9 p- k) E2 R0 Ljump/back:
% \' I1 u* r# r& [; melse
$ N# C7 c8 U" Q7 Z) m# k. U  Kjump/l1:
endif
l1:
+ K# E4 @% s: C% G0 sifthen/k<150 or k>350
) r9 W* a; u( I, t) Jmessg/'轮胎宽度超出范围(150-350)，请重新输入'
9 Y9 T7 X8 L% i7 h  Y& N1 U: h; ajump/back:
else
8 m+ c3 N. k0 i* Njump/l2:
endif
l2:
nd=ndi*1000/36
* w( k' C- p1 j5 Q* Mwd=1.5*nd
nr=nd/2
4 V# C* [+ O! [wr=wd/2
$$生成半轮胎周向截面点、线
pt(1)=point/(-k/2*0.93),(0.98*wr)
- v7 x4 i0 H+ g# U5 `5 R5 Fpt(2)=point/(-k/4),(0.99*wr)
pt(3)=point/0,wr
pt(4)=point/(-k/2),(wr+nr)/2
pt(5)=point/(-k/2*0.93),nr
5 W9 O: T0 K4 z1 ^& ~0 x8 x- S- Mpt(6)=point/pt(5),delta,(k/30),(-0.1*nr),0
pt(7)=point/0,0.9*nr
& F3 Z1 X* u* T. Z6 fpt(8)=point/pt(1),delta,5,-5,0
pt(9)=point/pt(6),delta,5,5,0
pt(10)=point/pt(5),delta,5,0,0
cr(1)=circle/pt(3),pt(2),pt(1)
- U( K3 R+ Z  f8 I! |cr(2)=circle/pt(1),pt(4),pt(5)
ln(2)=line/pt(5),pt(6)
ln(3)=line/pt(6),pt(7)
+ w2 @: B& |6 n; ^+ Z; x7 ~ln(4)=line/pt(7),pt(3)
$$倒角处理
+ q' u, L" ]% Vobj1(1)=fillet/cr(1),cr(2),center,pt(8),radius,15
9 a# r2 o1 H: g5 s6 j, e0 Xobj1(2)=fillet/cr(2),ln(2),center,pt(10),radius,15
6 |7 _' F! O7 c! Q: @obj1(3)=fillet/ln(2),ln(3),center,pt(9),radius,15
$$旋转
% y! M' b8 N. P, B0 aent(1)=solrev/cr(1..2),ln(2..4),obj1(1..3),origin,0,0,0,atangl,360,axis,1,0,0
8 Y+ D0 @. h% y8 D$$花纹线
ln(5)=line/-k/2,k/8,wr+10,-k/4,k/8,wr+10
ln(6)=line/-k/4,k/8,wr+10,-k/6,0,wr+10
ln(7)=line/-k/2,k/8,wr+10,-k/2,k/4,wr+10
ln(8)=line/-k/2,k/4,wr+10,-k/5,k/4,wr+10
ln(9)=line/-k/5,k/4,wr+10,-k/24,0,wr+10
ln(10)=line/-k/24,0,wr+10,-k/6,0,wr+10
/ N0 j7 |4 y( y$$切花纹
5 ^. X# ]/ V" Q0 h7 `1 Rmat2=matrix/mirror,ln(10)
, Z# ?& ?" a" U5 }5 ~obj1(5)=solext/ln(5..10),height,10+wr/30,axis,0,0,-1
obj1(6)=transf/mat2,obj1(5)
obj1(7)=unite/obj1(5),with,obj1(6)
# Q: C# g9 L# y  Ci=intf(3.1415926*wd/(3*k/8))
4 Y4 i# ?9 M: w9 x* Hn=1
( f3 C3 y/ Y0 T2 ?( Y" p: V7 jj=8
xh1:
6 r4 S' e7 d) C: ~! gifthen/n<=i-1
9 h5 h& j6 y1 ?1 \; P/ \  gmat3=matrix/yzrot,n*(360/i)
obj1(j)=transf/mat3,obj1(7)
: E% t' q  r2 M: A$ sj=j+1
n=n+1
7 Y. j$ F$ F; N6 h# M" ?jump/xh1:
. V/ a. o/ ^# i2 fendif
ent(2)=subtra/ent(1),with,obj1(7..j-1)
5 U5 @3 i1 j6 W4 u3 Cent(3)=transf/mat1,ent(2)
' l# _7 l; x& T7 dmat4=matrix/yzrot,360/i/2
ent(4)=transf/mat4,ent(3),move
1 E1 y% s# y1 h( ?& P5 C3 oent(5)=unite/ent(2),with,ent(4)
2 ]" w# o- m: k&color(ent(5))=&gray
1 F; B+ [* b# p3 g$ r, s+ S0 ?+ n$$----------------------轮毂--------------------$$
$$轮毂截面点、线
pt(11)=transf/mat1,pt(6)
pt(12)=point/pt(6),delta,0,-wd/40,0
* B. k* U' b- b5 kpt(13)=transf/mat1,pt(12)
2 m: A& M% U6 s; r! P) ~6 q" Npt(14)=point/pt(7),delta,0,-wd/40*2,0
* K- `2 V+ }4 v* B! [* R! M" vln(11)=line/pt(11),pt(6)
ln(12)=line/pt(6),pt(12)
ln(13)=line/pt(11),pt(13)
cr(3)=circle/pt(12),pt(14),pt(13)
pt(15)=point/pt(14),delta,-k/5,wd/30,0
pt(16)=point/pt(15),delta,-k/10,0,0
ln(14)=line/pt(15),pt(16)
9 @3 L( Q) r* }8 ~% u  C: Lpt(17)=point/pt(15),delta,-k/30,-0.2*nr,0
pt(18)=point/pt(17),delta,-k/15,-0.2*nr,0
+ c" D, _9 p% i( Z  ^pt(19)=point/pt(18),delta,-k/10,-0.2*nr,0
, C! L$ W8 K# Fpt(20)=point/-0.4*k,0
2 s0 o9 W' d# u+ u* u+ Q7 K7 ~pt(21)=point/pt(17),delta,-k/10,0,0
3 ^! W1 c1 x9 M6 i7 |pt(22)=point/pt(18),delta,-k/10,0,0
3 |3 ]7 {9 o/ t9 R$ f" opt(23)=point/pt(19),delta,-k/10,0,0
* B: d" P9 D! z6 @pt(24)=point/-0.5*k,0
* i9 ]4 ~+ j0 p! ?# Qcr(4)=circle/pt(18),pt(17),pt(15)
cr(5)=circle/pt(18),pt(19),pt(20)
cr(6)=circle/pt(22),pt(21),pt(16)
cr(7)=circle/pt(22),pt(23),pt(24)
$ U3 C' r# L+ A' J$ L. i; zln(15)=line/pt(20),pt(24)
$$旋转、倒棱
! v9 f9 w3 t8 Y+ `8 |ent(6)=solrev/ln(11..13),cr(3),origin,0,0,0,atangl,360,axis,1,0,0
blend/ent(6),radius,10
ent(7)=solrev/ln(14..15),cr(4..7),origin,0,0,0,atangl,360,axis,1,0,0
ent(8)=unite/ent(6),with,ent(7)
&color(ent(8))=&white
$$修型
$ w( E* p/ T" k$ G3 B; jobj2(1)=solcyl/origin,-k,0,0,height,k*2,diamtr,0.3*nr,axis,1,0,0
$ o' X6 @6 o$ m  l; Uent(9)=subtra/ent(8),with,obj2(1)
obj2(2)=solcyl/origin,-k,0.6*nr,0,height,2*k,diamtr,0.2*nr,axis,1,0,0
$ A# z* T+ |2 j. O' k+ q9 v6 nm=intf(3.1415926*nr/(0.4*nr))
g=1
w=3
xh2:
ifthen/g<=m-1
7 w  E5 F$ N0 f* @* Zmat5=matrix/yzrot,g*(360/m)
2 g  m. u8 X9 D* b' _obj2(w)=transf/mat5,obj2(2)
3 I# |! r" E% _% a- q, ~w=w+1
% C, c; |* \. ~' B/ Pg=g+1
jump/xh2:
$ M9 t% E; B$ v& p, G  Wendif
' i2 r0 v+ k+ p- j" t: _ent(10)=subtra/ent(9),with,obj2(2..w-1)
$$消隐辅助点、线
9 R& X, Z- h( B# Ublank/pt(1..24),cr(1..7),ln(1..15),obj1(1..3)
' T5 p+ d! U4 l4 Acancel:
halt

longlonglm

额 这。。。怎么没有人发表一下观点啊

longlonglm

试过了程序完全正确 如果能自己写出来 估计GRIP 学的就差不多了吧

davidcad

感謝分享,努力學習