整套的3d輪胎grip程式

dd007ok

那里有整套的3d輪胎grip程式？

ruju

entity/pt(100),ln(100),cr(100),obj1(100),obj2(100),ent(100)
number/nd,ndi,nr,k,wd,wr,mat1(12),mat2(12),mat3(12),mat4(12),mat5(12)
. v. U6 D) X) l, z! T$ s! \data/ndi,23,k,250
ln(1)=line/0,-100,0,100
mat1=matrix/mirror,ln(1)
+ k9 n0 _8 v3 s& Q$$---------------------轮胎--------------------$$
$$输入轮胎相应尺寸参数
back:
3 G+ ?7 V3 }1 j' o, tparam/'输入参数','轮辋直径(in)',ndi,'轮胎宽度(mm)',k,rsp
jump/back:,cancel:,ok:,rsp
( Q! o% E& M; B% Z5 Z$ s- [ok:
$$判断参数正误
ifthen/ndi<14 or ndi>25
. ~) i' a" [; t0 b6 O" O  pmessg/'轮辋直径超出范围(14-25)，请重新输入'
* B7 ^6 K+ U+ |" h1 I" ^jump/back:
else
3 \% F% R7 p. K3 \% w3 vjump/l1:
endif
( N2 U* B( A5 G! n0 zl1:
ifthen/k<150 or k>350
- y" [) Q# X6 xmessg/'轮胎宽度超出范围(150-350)，请重新输入'
" V: |3 S1 r! njump/back:
& z' A2 v2 D" Z: Ielse
jump/l2:
  j! @9 Q# ?, ?0 J, Bendif
8 W+ _# D6 c: ?2 M( sl2:
nd=ndi*1000/36
( Z- H% h; d6 t1 `6 |/ Y- `wd=1.5*nd
% K7 A- S8 s) A  S& x* v* xnr=nd/2
wr=wd/2
$$生成半轮胎周向截面点、线
pt(1)=point/(-k/2*0.93),(0.98*wr)
pt(2)=point/(-k/4),(0.99*wr)
pt(3)=point/0,wr
. i. g3 i- W$ xpt(4)=point/(-k/2),(wr+nr)/2
7 ^* W6 |( ^! a, }pt(5)=point/(-k/2*0.93),nr
pt(6)=point/pt(5),delta,(k/30),(-0.1*nr),0
pt(7)=point/0,0.9*nr
pt(8)=point/pt(1),delta,5,-5,0
pt(9)=point/pt(6),delta,5,5,0
pt(10)=point/pt(5),delta,5,0,0
6 ]3 ?5 T( \9 B6 B0 ^: l3 Scr(1)=circle/pt(3),pt(2),pt(1)
cr(2)=circle/pt(1),pt(4),pt(5)
1 W* Z% b) s8 i7 c6 Dln(2)=line/pt(5),pt(6)
ln(3)=line/pt(6),pt(7)
# R1 ~+ J8 Q. p0 ]6 b: Oln(4)=line/pt(7),pt(3)
, a! f  R- M- }+ X$ z- s" q3 _+ U$$倒角处理
obj1(1)=fillet/cr(1),cr(2),center,pt(8),radius,15
obj1(2)=fillet/cr(2),ln(2),center,pt(10),radius,15
obj1(3)=fillet/ln(2),ln(3),center,pt(9),radius,15
3 |% x+ |. f4 Z) l7 A$$旋转
5 A, T  T6 [  Nent(1)=solrev/cr(1..2),ln(2..4),obj1(1..3),origin,0,0,0,atangl,360,axis,1,0,0
8 F- c4 y9 G, T+ z/ {$$花纹线
ln(5)=line/-k/2,k/8,wr+10,-k/4,k/8,wr+10
# P: c% k0 W9 I# O- ^: g; lln(6)=line/-k/4,k/8,wr+10,-k/6,0,wr+10
, F; ?1 d# D( f) ~% R' Hln(7)=line/-k/2,k/8,wr+10,-k/2,k/4,wr+10
7 L0 d2 n% I8 D  X" Iln(8)=line/-k/2,k/4,wr+10,-k/5,k/4,wr+10
" i( H1 o* @: g  P: \+ o- xln(9)=line/-k/5,k/4,wr+10,-k/24,0,wr+10
ln(10)=line/-k/24,0,wr+10,-k/6,0,wr+10
- K6 `5 f& S9 a& S! F9 ]$$切花纹
mat2=matrix/mirror,ln(10)
obj1(5)=solext/ln(5..10),height,10+wr/30,axis,0,0,-1
, ^- i* F6 |- y# y+ e2 W9 S4 ]( kobj1(6)=transf/mat2,obj1(5)
! W, z) B& I5 Qobj1(7)=unite/obj1(5),with,obj1(6)
i=intf(3.1415926*wd/(3*k/8))
n=1
/ k1 N  w5 _  F2 Fj=8
xh1:
ifthen/n<=i-1
mat3=matrix/yzrot,n*(360/i)
obj1(j)=transf/mat3,obj1(7)
j=j+1
, r/ G) p: K1 O: Y# y, B, u4 rn=n+1
jump/xh1:
9 q9 O5 c6 V% ^6 \9 I2 ?" qendif
& t2 p6 Q  {$ `: w, Vent(2)=subtra/ent(1),with,obj1(7..j-1)
* h5 Z/ N  D! K0 A* yent(3)=transf/mat1,ent(2)
mat4=matrix/yzrot,360/i/2
ent(4)=transf/mat4,ent(3),move
ent(5)=unite/ent(2),with,ent(4)
&color(ent(5))=&gray
$$----------------------轮毂--------------------$$
: [% o4 @9 ~* J" ^$ r" Z7 }$$轮毂截面点、线
4 R% K2 j" l# h* j2 Kpt(11)=transf/mat1,pt(6)
pt(12)=point/pt(6),delta,0,-wd/40,0
pt(13)=transf/mat1,pt(12)
pt(14)=point/pt(7),delta,0,-wd/40*2,0
ln(11)=line/pt(11),pt(6)
  y( e0 s: M0 `  Eln(12)=line/pt(6),pt(12)
4 q) C) e% r) x$ ?; wln(13)=line/pt(11),pt(13)
cr(3)=circle/pt(12),pt(14),pt(13)
/ y. y: M9 O5 q+ bpt(15)=point/pt(14),delta,-k/5,wd/30,0
; [" g, e3 G8 N3 Y6 L2 {4 a5 ept(16)=point/pt(15),delta,-k/10,0,0
1 u8 W3 B$ c( P  U9 ?ln(14)=line/pt(15),pt(16)
pt(17)=point/pt(15),delta,-k/30,-0.2*nr,0
pt(18)=point/pt(17),delta,-k/15,-0.2*nr,0
pt(19)=point/pt(18),delta,-k/10,-0.2*nr,0
pt(20)=point/-0.4*k,0
6 O: ^. h' ~: ?$ i  u4 v9 bpt(21)=point/pt(17),delta,-k/10,0,0
$ e, Q, S/ d$ `3 j* r. ypt(22)=point/pt(18),delta,-k/10,0,0
pt(23)=point/pt(19),delta,-k/10,0,0
" h6 k7 r. d* E, i* @+ x  o/ N- U6 rpt(24)=point/-0.5*k,0
* Z8 J; n1 X" Y6 F2 E( Y+ zcr(4)=circle/pt(18),pt(17),pt(15)
cr(5)=circle/pt(18),pt(19),pt(20)
cr(6)=circle/pt(22),pt(21),pt(16)
8 F3 u& e8 p) {, L) z& }4 ocr(7)=circle/pt(22),pt(23),pt(24)
ln(15)=line/pt(20),pt(24)
# m1 w: A6 O8 S1 M, f1 \. L$$旋转、倒棱
$ c$ [8 G8 W, X. L( lent(6)=solrev/ln(11..13),cr(3),origin,0,0,0,atangl,360,axis,1,0,0
blend/ent(6),radius,10
ent(7)=solrev/ln(14..15),cr(4..7),origin,0,0,0,atangl,360,axis,1,0,0
ent(8)=unite/ent(6),with,ent(7)
9 P$ F) c3 N! [&color(ent(8))=&white
$$修型
) c3 R: x, ~2 W% \* z/ F: Dobj2(1)=solcyl/origin,-k,0,0,height,k*2,diamtr,0.3*nr,axis,1,0,0
ent(9)=subtra/ent(8),with,obj2(1)
, L5 i- J) ^5 |* l+ I7 Zobj2(2)=solcyl/origin,-k,0.6*nr,0,height,2*k,diamtr,0.2*nr,axis,1,0,0
m=intf(3.1415926*nr/(0.4*nr))
g=1
w=3
xh2:
% x0 Z  t$ C1 A- i& w- r8 difthen/g<=m-1
mat5=matrix/yzrot,g*(360/m)
. L) h" D. {! L- Q- tobj2(w)=transf/mat5,obj2(2)
: }( z) _- y, d/ `w=w+1
) R5 M/ N; S+ P4 [! h. ~& Ug=g+1
7 b$ F3 _, x9 R/ h5 Zjump/xh2:
endif
ent(10)=subtra/ent(9),with,obj2(2..w-1)
! o: S$ y& c2 h# K9 v9 A, l5 ]$$消隐辅助点、线
blank/pt(1..24),cr(1..7),ln(1..15),obj1(1..3)
- F8 I2 r0 `+ U8 [8 y9 Z/ Ucancel:
* S7 g- q0 H/ S4 f2 Uhalt

longlonglm

额 这。。。怎么没有人发表一下观点啊

longlonglm

试过了程序完全正确 如果能自己写出来 估计GRIP 学的就差不多了吧

davidcad

感謝分享,努力學習