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该函数的用法UF_MODL_replace_features 问题描述:
0 e4 Z1 K) ~. } m0 A [现在画两条线,将其中一条拉伸成面,然后进行如下操作:用未拉伸的线去替换拉伸的线,并使得拉伸的面也移动到未拉伸的线出,也就是子特征也拷贝过去,我用上面的函数UF_MODL_replace_features操作发现拉伸特征并没有拷贝过去,单步调试发现返回值不为0,最后一个参数n_parent_map为巨大的负数,看了英文帮助发现有点难懂,遂请大侠帮忙看看如何实现我的功能单靠这个函数是否能实现,如果能我的参数设置是不是错误了,错在哪儿?
. g, r6 ~+ t4 `8 X- H8 T代码:
- s; d6 L$ f9 O+ a) z/ Q UF_MODL_replace_features_t *replm_map=NULL;//帮助写可为输入/输出参数,我作为输入,不知道正确与否7 n# P: \+ J+ P# T4 ^1 e
int n_replm_map;//
8 ]. r5 q8 v2 O. [8 A6 L errorCode =UF_MODL_replace_features(&first_element,1,&second_element,1,true,true,&replm_map,&n_replm_map);/ m5 |; ~4 X$ |& Q1 U& d" N
+ G: Q- Q% ~7 D4 N函数注释:(小弟英文水平和理解力有限请大侠帮忙)
4 v3 A' s) ?- MThis function replaces the features in original_features[] by the Z- u3 k) O1 K; j/ f
features in replacement_features[] or the copies of features in " z! ^6 y1 h& Q; W }8 ?" W4 }4 ?
replacement_features[] if original_features[] are features on bodies,
7 ~! N! \* |6 p" x. Bcurve features and datum features. The children of the original_features[] 4 r* z9 W6 m/ C' G. g( a
will be reparented to the replacement_features[] or copies. 9 q3 ~/ f: X) @# r1 w- `- j
, G" D. Q3 I3 Q8 ~) u& _. KThe original features will be deleted. ( w2 i8 }8 {6 r7 V; E F6 w
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original_features[] can contain: features on the same body, curve features, ' D u8 p; L1 u( y6 J2 V: N! r: z
datum plane and datum axis features.
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" \* c2 F5 c7 Y0 dreplacement_features[] must contain: features on other bodies (if : K G9 h+ K! @- i4 J5 `
original_features[] contains features on a body), other curve features
- P2 d$ J& R j) M0 X- s(if original_features[] contains curve features) and other datum plane ) B; J0 @0 E- m" E2 ?, w1 S" \0 t
and other datum axis features (if original_features[] contains datum plane
2 Q0 a8 I$ X# zor datum axis features). ; N) O' \( G- v4 D6 E4 P
$ Q# J8 x- O7 b, qNote that original_features[] and replacement_features[] must contain ! J, x7 R2 Z2 z8 W2 u7 Q5 X. [
features that are in the same part file. Also, for features on a body, the ! @# S$ x4 y; U6 I# }2 }! ^( R9 v
parents of each of the features in replacement_features[] must be either
T! Q4 ~( c4 s- zanother feature in the replacement_features[] or must be a feature which
) R# ^; q6 Z. W4 t: N; t8 {0 C, }9 his before the earliest feature in the original_features[].
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* @& o* T2 m" H8 d7 l w5 Y4 x. eparent_map[] maps entities created by the original_features[] to the " m. }8 I. E! m* u9 _
corresponding entities on the replacement_features[]. In addition to the
0 j6 c e" @5 j( G0 |4 Qoriginal_features[] and replacement_features[] you will have to provide a map 5 s0 Y5 x- t: ^" n6 T
of edges and faces on the original_features[] to the corresponding edges and
* t, Z, j# Z% ?, X6 T' O, zfaces of the replacement_features[].
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You will specify the map as a array of objects of type
" u+ b3 p' W; N' M, u* R2 ?UF_MODL_replace_features_t described below. The children of the
. |' n9 G& Q. J& K: p0 | i" `: Eoriginal_features[] will be reparented to copies of the corresponding , u- O U: N6 D) o, K
entities on the replacement_features[] that are specified in the parent_map[]. & E5 n: o4 F: d+ |& J8 K' J) z
$ M8 X+ u+ Q2 w5 b% ^Calling this function with return_map as true does not perform the replacement
4 u& [. z1 o* g( r9 u# rbut returns a parent_map[] each of whose original_entity elements are edges
* _/ l# e0 c2 iand faces created by original_features[]. Only those edges and faces that are
: M9 k! Y8 c+ Sparents of downstream features are returned in the parent_map[]. The % v: x- o& y0 Y B$ L( C5 a
replacement_entity elements of all the structures in the parent_map[] are 0. 6 ^) Z$ |6 c# D7 ]# x$ O
You will have to assign the appropriate replacement_entity for each of
1 y. d- N( V5 C" l* F5 \the structures returned in the parent_map[] before calling this function with
3 H4 \4 ]: v9 I3 R. c2 s. Areturn_map as false to perform the actual replace. : E% @6 m2 e( u# r6 @: i7 x
参数示意:- A3 s* J) V4 ^* k0 Y5 d: n
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[ 本帖最后由 mydear 于 2008-6-25 12:20 编辑 ] |
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