这儿要是没人帮我解决，以后我就不来这儿了

mydear

该函数的用法UF_MODL_replace_features                                                                                                                                                                                                                                                                                                                        问题描述：
现在画两条线，将其中一条拉伸成面，然后进行如下操作：用未拉伸的线去替换拉伸的线，并使得拉伸的面也移动到未拉伸的线出，也就是子特征也拷贝过去，我用上面的函数UF_MODL_replace_features操作发现拉伸特征并没有拷贝过去，单步调试发现返回值不为0，最后一个参数n_parent_map为巨大的负数，看了英文帮助发现有点难懂，遂请大侠帮忙看看如何实现我的功能单靠这个函数是否能实现，如果能我的参数设置是不是错误了，错在哪儿？
代码：
& g. x! I* ]6 M: Z  u- Q6 s        UF_MODL_replace_features_t *replm_map=NULL;//帮助写可为输入/输出参数，我作为输入，不知道正确与否
: S( |1 I. z! H) k( \        int n_replm_map;//
        errorCode =UF_MODL_replace_features(&first_element,1,&second_element,1,true,true,&replm_map,&n_replm_map);

7 X0 W: r* v2 D: Z, r函数注释：（小弟英文水平和理解力有限请大侠帮忙）
This function replaces the features in original_features[] by the
6 b* X; C: R6 X7 z- Q7 e+ nfeatures in replacement_features[] or the copies of features in
. _# L' }) ?7 g' C/ lreplacement_features[] if original_features[] are features on bodies,
curve features and datum features. The children of the original_features[]
0 X* u" r$ o! e  |* _! }will be reparented to the replacement_features[] or copies.
+ f9 y$ r) k, ~
The original features will be deleted.
. ?+ ^1 k* u. F3 D2 g/ v; u
2 ]$ n+ g. ?# U2 M4 Boriginal_features[] can contain: features on the same body, curve features,
' }# \. o" A- ], gdatum plane and datum axis features.
7 q- r) j" w) v! Q
9 t, ]5 o5 G( K/ `8 mreplacement_features[] must contain: features on other bodies (if
# V& [5 y3 t, w! |/ l# Moriginal_features[] contains features on a body), other curve features
' [/ t# g3 [4 \* L6 o  h(if original_features[] contains curve features) and other datum plane
5 F: |$ i- c" {! r5 qand other datum axis features (if original_features[] contains datum plane
# O9 K! G1 v) @8 D6 j- Uor datum axis features).
* B8 x" {+ w7 g1 {
Note that original_features[] and replacement_features[] must contain
features that are in the same part file. Also, for features on a body, the
' V- Z8 h3 ?  ?5 {! e0 S( Bparents of each of the features in replacement_features[] must be either
2 H3 w, J* T- }4 K* T8 panother feature in the replacement_features[] or must be a feature which
5 r( M$ E8 f% s) Lis before the earliest feature in the original_features[].
% S' n9 \: `5 I7 {! X
+ m3 S- ~+ O( e  Dparent_map[] maps entities created by the original_features[] to the
7 y( b: x% r7 l& o$ S0 g+ D! ]& ?! {corresponding entities on the replacement_features[]. In addition to the
original_features[] and replacement_features[] you will have to provide a map
of edges and faces on the original_features[] to the corresponding edges and
faces of the replacement_features[].
8 T; B+ x. u/ I* |5 H0 _8 z3 h
. c" L3 i5 x, s# _- F! i6 Q! iYou will specify the map as a array of objects of type
UF_MODL_replace_features_t described below. The children of the
" m+ S1 h( X% R% Joriginal_features[] will be reparented to copies of the corresponding
) n6 y3 q3 {7 w' F) @+ uentities on the replacement_features[] that are specified in the parent_map[].
' T5 r4 w1 ^9 w/ }# d& ]: \' Z6 E
* K+ h4 I% x% D, A+ z. g, CCalling this function with return_map as true does not perform the replacement
but returns a parent_map[] each of whose original_entity elements are edges
and faces created by original_features[]. Only those edges and faces that are
parents of downstream features are returned in the parent_map[]. The
replacement_entity elements of all the structures in the parent_map[] are 0.
You will have to assign the appropriate replacement_entity for each of
the structures returned in the parent_map[] before calling this function with
return_map as false to perform the actual replace.
7 [1 X2 z0 ^/ v; Y  Q; X3 D, L8 C参数示意：
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/ Z/ _& H. t$ l& j2 l, D[ 本帖最后由 mydear 于 2008-6-25 12:20 编辑 ]

wangbangjian

这儿是没人帮你解决了

yxq126520

看不懂

wjw11221

貌似这人还在这蹦达