UG GRIP建模源代码实例_方向盘

xcb

原帖地址：http://www.ugufun.com/?p=128
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2014-3-24 21:30 上传

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这是个简单的建模实例，用了回转体、拉伸、以及布尔运算。

entity/ln(100),cr(100),pt(100),obj(100),ent(10),csys1,csys2
4 J1 f! b! t1 Fnumber/mat1(12)
data/d,600
back:
( \( `4 O) c" y5 Q" aparam/'输入方向盘平均直径','方向盘平均直径(mm)',d,rsp
jump/back:,cancel:,ok:,rsp
ok:
$$尺寸判断
ifthen/d<500 or d>1000
" }! A0 g  k8 J  Dmessg/'尺寸超出范围（500-1000），请重新输入'
jump/back:
6 m% d" h" D7 velse
3 x1 |1 p2 C" d; o! L2 Ojump/l1:
endif
l1:
$$外圈
# |. c: N& k" f9 K* \" I- n/ kr=d/30
6 e+ |- W7 R3 Z* W+ Z4 _pt(1)=point/0,7*d/15
cr(1)=ellips/pt(1),r,1.5*r
ent(1)=solrev/cr(1),origin,0,0,0,atangl,360,axis,1,0,0
- h- _4 Z& a/ C+ x+ i$$旋转坐标
ln(1)=line/0,0,-1,0,0,1
ln(2)=line/0,-1,0,0,1,0
csys1=csys/ln(1),ln(2)
: g! u( m, @: |& ~, g9 h$ d% j&wcs=csys1
' v% U- z. Z9 Q3 v9 j, A; N9 }+ V$$辐条
- e, |, V6 ^: V; @+ q( \2 p  O/ dpt(2)=point/0,d/20,r
( Q/ J4 S2 a3 B- _8 n* e; W- Bpt(3)=point/7*d/30,d/10,r
& v# g, V. _1 J2 F9 Upt(4)=point/7*d/15,d/10,r
cr(2)=circle/pt(4),pt(3),pt(2)
$ @) ]: F$ q/ ?5 h% P4 w2 b9 Ypt(5)=point/0,0
ln(3)=line/pt(5),atangl,-60
mat1=matrix/mirror,ln(3)
/ n) O5 n; e; q3 h- ?; ccr(3)=transf/mat1,cr(2)
pt(6)=point/endof,xlarge,cr(3)
2 p+ g4 s! P! O0 g3 v. xln(4)=line/pt(2),pt(6)
" Y/ [7 j/ ^% A- j( F% u" G' M$ ppt(7)=point/0,0,r
; X8 m, e( ]. {) u6 m% y' Bobj(1)=fillet/cr(2),ln(4),center,pt(7),radius,50
obj(2)=fillet/ln(4),cr(3),center,pt(7),radius,50
5 a/ u$ ^$ W/ \, K/ D( ]. f- _1 ]$ j# Opt(8)=point/pt(4),delta,0,-d/10,0
5 U6 s9 d" O; L' d" s8 y2 N/ N/ {% qpt(9)=point/pt(7),delta,d*(cosf(60))/8,-d*(sinf(60))/8,0
pt(10)=transf/mat1,pt(8)
cr(4)=circle/pt(8),pt(9),pt(10)
' }; u; b0 A$ Y4 Z- ypt(11)=point/endof,xsmall,cr(3)
ln(5)=line/pt(11),pt(10)
ln(6)=line/pt(8),pt(4)
) e1 p* g& l$ _4 }" ~$ aent(2)=solext/cr(2..4),obj(1..2),ln(4..6),height,2*r,axis,0,0,-1
blend/ent(2),radius,10
$$旋转坐标
$ q* w- b6 |# \6 O% X3 R1 kln(7)=line/pt(5),perpto,ln(3)
csys2=csys/ln(7),ln(3)
&wcs=csys2
( y; f& R( V. A7 \6 F( r8 x! M$$生成联轴部分
ent(3)=solcyl/origin,0,0,-1.3*r,height,2.6*r,diamtr,d/5,axis,0,0,1
9 z+ S; y1 Q# \& N/ E. Kblend/ent(3),radius,10
cr(5)=circle/0,0,-1.3*r,d/15
cr(6)=circle/0,0,-1.3*r,d/30
ent(4)=solext/cr(5..6),height,4*r,axis,0,0,-1
' d, ~5 I' I; L( ~, C( @7 `. Uent(5)=unite/ent(1),with,ent(2..4)
$$隐藏多余实体
blank/cr(1..6),ln(1..7),pt(1..11)
, N. O# j/ g; n1 i" ^) |( h$$上色
8 H1 P  L/ j8 }) k+ }2 C&color(ent(5))=&gray
cancel:
: c3 z( V2 p. d3 Nhalt

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pengfei2010

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