UG GRIP建模源代码实例_方向盘

xcb · 发表于 2014-3-24 21:30

原帖地址：http://www.ugufun.com/?p=128

fangxiangpan.rar (1.27 KB, 下载次数: 57)

这是个简单的建模实例，用了回转体、拉伸、以及布尔运算。

entity/ln(100),cr(100),pt(100),obj(100),ent(10),csys1,csys2
, F: X- r- ^2 J+ a/ Znumber/mat1(12)
0 Z4 D) z5 u6 N/ P9 `4 {; O; Ydata/d,600+ K3 ?4 X% v2 y( f& Z
back:9 X! c1 s) X$ Z& C2 s' P* }9 B
param/'输入方向盘平均直径','方向盘平均直径(mm)',d,rsp
- a% ?$ T+ E# L! zjump/back:,cancel:,ok:,rsp& A" B3 x: P# R% o& Q/ T
ok:
+ @% q2 ?9 c" e4 N( R4 u# x3 B2 _$ J0 ^$$尺寸判断
+ {4 @' W" B& o3 g3 Gifthen/d<500 or d>1000/ w$ k9 f' d4 w' G
messg/'尺寸超出范围（500-1000），请重新输入'7 a2 {) G3 C  b! k& {; q$ W% l* r5 H
jump/back:
% ?) q- b& T) G. Y0 Jelse2 T2 \( y) \5 C& t
jump/l1:
$ z+ Y4 Z8 o2 j. X( v: A. Iendif
: U4 c$ v1 n* W2 K- k7 D* |8 f% Gl1:% b% B# Z. E% |* n3 W4 K6 N+ j
$$外圈! w. s5 Z% J1 t! B
r=d/30* n' v) G' l/ U
pt(1)=point/0,7*d/15' g( A% w, q3 h! k7 O6 J
cr(1)=ellips/pt(1),r,1.5*r2 c- B$ D9 m# U8 L; c, D
ent(1)=solrev/cr(1),origin,0,0,0,atangl,360,axis,1,0,0
. Q' ~4 x1 W9 C: S7 h$$旋转坐标
' s/ l- H: d+ R; Aln(1)=line/0,0,-1,0,0,1
3 c2 h$ G' m5 d7 K7 yln(2)=line/0,-1,0,0,1,0
" e; a4 b& f4 r5 Bcsys1=csys/ln(1),ln(2)
, ~0 L! e0 @) Y  |8 Q! g&wcs=csys1
1 z; |0 @# s+ l8 x4 Y$$辐条
1 l3 ^. x6 ~' apt(2)=point/0,d/20,r' n+ H& ?. b+ y, r) w& K
pt(3)=point/7*d/30,d/10,r
' s7 \' z% O  g8 k% l1 z4 Fpt(4)=point/7*d/15,d/10,r
9 e2 r8 t% [# ?$ Y$ p$ {cr(2)=circle/pt(4),pt(3),pt(2)7 \$ s+ ^( y) H, G+ @
pt(5)=point/0,0
8 E; N5 i" W! E* B$ lln(3)=line/pt(5),atangl,-60
+ ~3 U! L0 o- smat1=matrix/mirror,ln(3)/ C4 p' N" u1 y% ?; p# f' ]
cr(3)=transf/mat1,cr(2)
8 Q8 B3 `" J9 j7 y) Ypt(6)=point/endof,xlarge,cr(3)6 w% f0 [! f- }9 Z: A  v) U' K
ln(4)=line/pt(2),pt(6)
4 S4 z5 V. K) I4 x, bpt(7)=point/0,0,r! a5 p* J& [7 |* T; ]7 }+ q
obj(1)=fillet/cr(2),ln(4),center,pt(7),radius,50
7 X! H$ a& ]  I' J2 J# z# {obj(2)=fillet/ln(4),cr(3),center,pt(7),radius,50& H) N5 L+ Z1 i. W$ s, i$ U$ F
pt(8)=point/pt(4),delta,0,-d/10,0
/ b) c( h9 Z3 n. A9 B# dpt(9)=point/pt(7),delta,d*(cosf(60))/8,-d*(sinf(60))/8,0
/ b# A4 E: G, tpt(10)=transf/mat1,pt(8)
+ R( }! U! i! H2 m& q4 h9 _cr(4)=circle/pt(8),pt(9),pt(10)
: m, c$ p6 j2 Apt(11)=point/endof,xsmall,cr(3)" f) e) j- L% E5 v, U# a6 G& }
ln(5)=line/pt(11),pt(10)8 I2 c) \+ X& k0 S) \
ln(6)=line/pt(8),pt(4)
( r: k5 X# M' U  ient(2)=solext/cr(2..4),obj(1..2),ln(4..6),height,2*r,axis,0,0,-15 q& ?/ M6 Q0 w
blend/ent(2),radius,10
0 I; ~" r/ n' ^, s$$旋转坐标' d4 {! r3 N, z( H
ln(7)=line/pt(5),perpto,ln(3)
3 _1 S7 Q; U7 V$ B8 X4 rcsys2=csys/ln(7),ln(3)
9 e8 I4 B3 P! ?&wcs=csys2' n7 b4 L" Q1 Z9 t5 K$ t
$$生成联轴部分0 a# v2 u- z& P/ r; q
ent(3)=solcyl/origin,0,0,-1.3*r,height,2.6*r,diamtr,d/5,axis,0,0,1! O$ P  p: u4 w
blend/ent(3),radius,10% F. ~/ n( _% o' b- R& _( h
cr(5)=circle/0,0,-1.3*r,d/15
$ J' M' A, g$ F9 Ucr(6)=circle/0,0,-1.3*r,d/30
; b* G" N+ H& }8 a$ G  tent(4)=solext/cr(5..6),height,4*r,axis,0,0,-1
; U6 q' v/ G9 _1 `. y8 t# nent(5)=unite/ent(1),with,ent(2..4)
9 R' \' x- \0 `+ L2 K2 ]/ d$$隐藏多余实体
& _7 p0 |- y, E" w. Fblank/cr(1..6),ln(1..7),pt(1..11)
- x% \$ f0 ?2 q$$上色& e2 _6 h- m* j4 l
&color(ent(5))=&gray( b. L* U+ T$ ?0 N, v! Y
cancel:& X0 _+ M4 t+ B2 V. m9 c6 ]
halt

努力活着 · 发表于 2014-9-25 22:41

大哥，厉害哦

pengfei2010 · 发表于 2017-1-22 19:10

好厉害学习了

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