UG GRIP建模源代码实例_方向盘

xcb · 发表于 2014-3-24 21:30

原帖地址：http://www.ugufun.com/?p=128

fangxiangpan.rar (1.27 KB, 下载次数: 57)

这是个简单的建模实例，用了回转体、拉伸、以及布尔运算。

entity/ln(100),cr(100),pt(100),obj(100),ent(10),csys1,csys21 q" I$ N( o0 G
number/mat1(12)3 L& g& d4 N& u4 |! E
data/d,600
2 O* x2 c6 p5 o- }/ Dback:. R. {$ P3 z0 `) o+ C
param/'输入方向盘平均直径','方向盘平均直径(mm)',d,rsp
+ K( S6 M( X. X1 Tjump/back:,cancel:,ok:,rsp
0 m$ L. ~7 V1 j" e, I4 Q" r7 |6 B+ cok:: B' [% i, k# @9 U* A$ Y
$$尺寸判断
0 J  a% O0 ^! aifthen/d<500 or d>1000' E/ x3 ]1 d8 s+ j$ R; Y9 Y: x
messg/'尺寸超出范围（500-1000），请重新输入', n- M! y0 J; {
jump/back:
# E5 ^* i6 p" h* p; G5 o2 Yelse# @' W" Q, d- S
jump/l1:+ R9 D# ?7 c2 }/ n
endif# }" Y( Z$ r. Q! y1 z
l1:
! i' ~8 x( O: O7 z2 k3 z$$外圈( F, a+ y- d5 f  |2 g" s
r=d/30
" l: F, U& V  T) X) S- T7 Ppt(1)=point/0,7*d/157 E' @# d% G9 B' n; t+ h
cr(1)=ellips/pt(1),r,1.5*r( R) Q$ i: z; W3 U; _$ P* K
ent(1)=solrev/cr(1),origin,0,0,0,atangl,360,axis,1,0,0
: a) W; ?' E9 b; W! L% y5 o$$旋转坐标2 ~. B! `' B4 g/ X# L
ln(1)=line/0,0,-1,0,0,1
7 ]2 S% v  Q. V3 L- ]0 Rln(2)=line/0,-1,0,0,1,0! u' a. k5 y% w; ~1 L% c
csys1=csys/ln(1),ln(2): v# k5 H7 Y' j! V
&wcs=csys1
" E3 w/ I. b3 X$$辐条
3 s  l9 d$ F9 Lpt(2)=point/0,d/20,r
- W6 d6 t7 p" V: A0 @6 x+ z0 n& npt(3)=point/7*d/30,d/10,r
# @+ x/ r8 e" w0 Mpt(4)=point/7*d/15,d/10,r
' u5 n6 p! i* i9 b, h4 |cr(2)=circle/pt(4),pt(3),pt(2)
4 Q0 `$ V6 x3 j6 u+ opt(5)=point/0,0* `% J8 k6 R) P1 [9 G) D
ln(3)=line/pt(5),atangl,-60
% \/ ~: Q* t7 N" x4 |mat1=matrix/mirror,ln(3)' F% o- p9 ^' A: D
cr(3)=transf/mat1,cr(2)  W$ X: s, k" m
pt(6)=point/endof,xlarge,cr(3)( J- a' H* c5 I" I- j) U
ln(4)=line/pt(2),pt(6)
$ t/ R* C. z4 Y4 \( r9 |+ G+ Zpt(7)=point/0,0,r
8 L8 a7 y& e/ S4 @9 `0 T; bobj(1)=fillet/cr(2),ln(4),center,pt(7),radius,50; }( f) I9 [8 V0 P& b4 w
obj(2)=fillet/ln(4),cr(3),center,pt(7),radius,505 q9 h) }- b0 n7 N$ n* V% |
pt(8)=point/pt(4),delta,0,-d/10,04 `) ~5 u, Y& U  l2 g+ T
pt(9)=point/pt(7),delta,d*(cosf(60))/8,-d*(sinf(60))/8,05 h% {" ~2 o: z. E+ Z
pt(10)=transf/mat1,pt(8)
( w* _. B6 T' K+ y+ W) Zcr(4)=circle/pt(8),pt(9),pt(10)$ a2 E3 o6 t& a5 B- F, }
pt(11)=point/endof,xsmall,cr(3)
  V- ]* w% M) L/ H0 f* I% o% vln(5)=line/pt(11),pt(10)/ y5 K* G+ F4 E& c$ j( A7 w. O! `
ln(6)=line/pt(8),pt(4)8 s! D% t6 v" M
ent(2)=solext/cr(2..4),obj(1..2),ln(4..6),height,2*r,axis,0,0,-1
/ f" r% j" \( H( mblend/ent(2),radius,10/ f) P- T+ {5 x) C5 W+ b9 O. z' G& `
$$旋转坐标
2 l8 @; \" u' ?& Aln(7)=line/pt(5),perpto,ln(3)
1 R7 \! U( G$ w- l! B# Bcsys2=csys/ln(7),ln(3)6 C; R* b/ d- c; W/ Z
&wcs=csys23 z: p: }3 e* z' I# ?1 ^
$$生成联轴部分
) M% k" P+ r7 M0 @6 E5 ~: Fent(3)=solcyl/origin,0,0,-1.3*r,height,2.6*r,diamtr,d/5,axis,0,0,1
; d4 c3 ^; N$ B. dblend/ent(3),radius,100 R! j$ J4 K) r5 U
cr(5)=circle/0,0,-1.3*r,d/15
; ?% @/ V! A4 e8 z) c- zcr(6)=circle/0,0,-1.3*r,d/30& q8 c6 T! n% n0 N; N, s
ent(4)=solext/cr(5..6),height,4*r,axis,0,0,-1* \7 e! N# M/ N
ent(5)=unite/ent(1),with,ent(2..4)  d! F- T* ~7 i2 K
$$隐藏多余实体' e7 v! Y4 H# j' o3 I
blank/cr(1..6),ln(1..7),pt(1..11)$ K/ a- y8 _2 R  h# {
$$上色
' n/ L0 c  s6 |& }1 n4 b2 z&color(ent(5))=&gray, a( ~% H  @. j3 u: h. o
cancel:# Z/ e" t% o, a1 x7 v
halt

努力活着 · 发表于 2014-9-25 22:41

大哥，厉害哦

pengfei2010 · 发表于 2017-1-22 19:10

好厉害学习了

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