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发表于 2010-4-27 21:38
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- NUMBER/m,z1,z2,d1,t,i $$模数=m,蜗杆头数=z1,蜗轮齿数=z2,分度圆直径=d15 s* m& R% T9 A; P; d' N+ n
- entity/cyl,pt1,pt2,pt3,pt4,ln1,ln2,ln3,ln4,pt(5001),SPL,obj1,obj2,obj3,obj4% n0 k8 \! P6 S4 A; }
- $$ cy1为圆柱体,pt1..pt4为点,ln1..ln4为T型线,pt(5001)拟合点,spl为螺旋线
8 W, g2 I: L3 g" Y- B$ p( v6 N4 i - data/ha,1,c,0.2 $$ ha为齿顶高系数,c为径向间隙5 t1 c% i6 G* w* O, P% Z
- l10:
. U9 \8 X, s2 K - PARAM/'阿基米德蜗杆','模数 m=',m,$
: [" A" |# Z- t5 F5 Y0 u7 l, R% i - '蜗杆头数 z1=',int,z1,$
8 v! a9 D& O, |4 G$ a7 |& S - '蜗轮齿数z2=',int,z2,$
3 r0 C8 K3 {: V* o1 A' Y B2 } - '分度圆直径d1=',d1,respond
% U3 `4 n# ?( @) a9 u6 u - JUMP/l10:,stop:,,respond, j6 [7 X; m6 z) U4 b4 s0 X! N$ O4 C
- r=atanf(m*z1/d1) $$ r为导程角
- \& k s) a2 x- t7 M9 b+ a; F - px=3.1416*m $$ px为齿距
1 t4 w7 d! o& q# }# v$ i - da1=d1+2*ha*m $$ da1为齿顶圆4 K; J1 h, x V- Q4 }) R; e
- df1=d1-2*(ha+c)*m $$ df1为齿根圆; |7 O) }# W6 T$ Z( t. u6 ?+ b
- b1=2*m*sqrtf(z2+1) $$ b1为蜗杆齿宽(螺纹长度)4 S( ]9 U {9 T: y! B% n+ P
- n=INTF(b1/px)+2 $$ n=螺旋线圈数7 S5 }1 P! E) [7 G) ?
- cyl=solcyl/origin,0,0,px,height,b1,diamtr,da1,iferr,mark:/ B- i& m" |: H" V5 ?4 t" F& v
- mark:
: w' D) y) b$ a5 c, J* n: x - stop:5 K; s' L' ~1 s# q6 n
- pt1=POINT/df1/2,0,px/4-(d1-df1)/2*sinf(20)/cosf(20)
& l& Y1 \( s3 K5 |0 a - pt2=POINT/df1/2,0,(d1-df1)/2*sinf(20)/cosf(20)-px/4% N3 J5 Y, X9 }$ `
- pt3=POINT/(da1+0.1)/2,0,px/4+(da1-d1+0.1)/2*sinf(20)/cosf(20)/ C' Y3 g) M& _+ P7 o" \0 R# J
- pt4=POINT/(da1+0.1)/2,0,(d1-da1-0.1)/2*sinf(20)/cosf(20)-px/49 I, r1 ?, N+ ^7 w
- ln1=LINE/pt1,pt2) s7 ]4 U7 {6 \( s+ T5 {8 b* R% y
- ln2=LINE/pt3,pt4% _* ^: s# K, d
- ln3=LINE/pt1,pt3. U1 l" e" I# a! ^
- ln4=LINE/pt2,pt4
2 p1 u- E, v# v4 [5 H - i=0
) {: x% @- c- V) t4 s - str1:
- h! ?, m' K' U. }* s7 F8 Q v2 O - i=i+1 $$取i个拟合点
- d0 K8 g4 F9 n. `* R5 G$ L - t=(i-1)/5000 $$ t取0~1* p7 L8 k' q2 {6 f' ^3 \
- xc=cosf(360*n*t)*d1/21 A5 R& c9 W7 k
- yc=sinf(360*n*t)*d1/2
b# b+ e6 S- y - zc=t*px*n
) R7 S. H' z4 P+ @1 V - pt(i)=point/xc,yc,zc
! Q9 k! E4 a x7 r3 G. ^- h; R! \$ @ - if/t<1,jump/str1:
1 `8 z0 Q$ P; J1 r2 C) i D - # B- W7 w+ y* B2 @, E+ Q' ` K
- blank/pt(1..i)
) m( h V8 }4 X0 Y- Q2 z* \ - 7 H2 S2 b# o- U4 n
- SPL=spline/pt(1..i)
j) I2 j" j# |
+ J* E C1 V) Y, U1 s- $$生成B-曲面。1 d( s9 T. l" s2 ?
- 9 m0 H/ K$ Y, E* Y* n0 G( W3 r" l1 O
- obj1=bsurf/swpsrf,tracrv,SPL,gencrv,ln1[,ORIENT∣,zc∣]
; |" x, W" Y G; b - obj2=bsurf/swpsrf,tracrv,SPL,gencrv,ln2[,ORIENT∣,zc∣]5 O+ U/ F+ b+ |' X3 J
- obj3=bsurf/swpsrf,tracrv,SPL,gencrv,ln3[,ORIENT∣,zc∣]! E3 S2 x0 \8 j) p" F0 w) R+ v/ w
- obj4=bsurf/swpsrf,tracrv,SPL,gencrv,ln4[,ORIENT∣,zc∣]
. w- h2 E! O4 S. N. P# e$ S! f h - $$程序结束。2 }2 i1 q6 Z% p
- trm:- N+ h$ d' K- u4 d( D% e
- halt# r$ U. j" h) T2 v V
复制代码 找到了扫掠函数,但还是不怎么会用,我做的是蜗杆的扫掠,哪位大侠帮我看看问题在哪啊? |
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扫掠函数
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