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本帖最后由 caiyingkai 于 2010-6-6 16:41 编辑
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处理出来的程式放机器上跑+Z超程?) t9 _$ P2 k, z2 r
这程式怎么超程的?, C+ I+ \, ~& A& o$ a) ]
发那科系统!2 c. V. C2 n+ w1 |8 L$ \
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如下
d0 {) L& L" }3 e. IN0010 G00 G40 G49 G17 G80 G90+ v% W( J% n; q
N0020 G91 G28 Z0.0
/ v I. S( y' M7 v6 V% \5 Q) H( fN0030 T01 M06 U( e" U* F* X! x! I: }4 V
N0040 G00 G90 G54 X0.0 Y0.0
7 E; A+ A G. y0 ^, tN0050 M080 x9 U e0 y) s( t
N0060 S1800 M03
- p% f$ V8 o7 h- y: t Q0 lN0070 G94 G00 G90 X-27.6 Y0.0 A315.
! q O; r0 ]& e# Z$ W1 b+ J8 `N0080 G43 Z37.5 H01
+ J& G, X' ?3 I. V& @N0090 Z24.1 O% u+ S. x5 `* H0 ~
N0100 G01 Z21. F1000.
$ {4 ~0 I; I7 d% g$ u. ]N0110 X-10.& i7 R, J( V6 k' K z
N0120 X10.% D; e& b. ^; a: ]+ K" T
N0130 Z37.
! Z' H; R- Z) `2 }- C5 m$ S5 o+ dN0140 G00 X-27.6
/ L6 x' k: u+ I) T! nN0150 Z23.5: h5 `9 m5 s" H1 H C! T, \
N0160 G01 Z20.5
4 i3 U7 Z/ R& N) _N0170 X-10.
. \5 G; I& \0 I# G9 ]# |N0180 X10.: t1 P8 [8 w. k# l
N0190 Z36.55 ~5 h% \7 V" K2 Y7 K5 m% \
N0200 G00 X-27.6
, [ D# W6 n# f# m2 y. Z$ XN0210 Z23.+ K! L( ^5 l3 |% [- A6 P( k' H0 q
N0220 G01 Z20.+ x) y# [, f# ]- `, M4 G. o( B
N0230 X-10.( B( O% r- E3 d* f! {" G+ s
N0240 X10.
& b0 C% P, w1 a* z3 M8 aN0250 Z36.
$ ~5 U# T/ K' V' F7 p# Z; DN0260 G00 Z37.5* L( Z6 s4 Y) M5 a- T; d
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还有就是出来一个报警020$ _9 n) A6 N M
020 圆弧插补中,起始点和终点到圆心的距离的差大于876号参数指定的
0 b; ?! u9 C; H# E! f数值。. O8 l- c, F1 D7 m& }5 x
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这个是什么意思呢!我的程式为
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' \% g, Y; A- k% V! }6 b) JN0080 G43 Z30.5 H06
/ N3 C: ?8 `! ]+ f, yN0090 Z19.. s: D$ m$ T+ n
N0100 G03 X-.459 Y-1.265 I.5 J0.0 F800.
9 o, Z6 i) s( b$ L/ RN0110 X-.265 Y-1.459 I.459 J.2658 x% Y, h! N; q& S/ x$ ]
N0120 X0.0 Y-1.5 I.265 J.459' v8 u' ^7 H# G$ _* Y
N0130 X.266 Y-1.507 I0.0 J1.5, n% _ @9 V: G) ~" T
N0140 X.523 Y-1.438 I-.266 J1.5079 G' I4 {% A3 z
N0150 X.75 Y-1.299 I-.523 J1.438
* q# W* C8 I0 i7 r! jN0160 X1.238 Y-.899 I-.75 J1.299
' K+ n. S, Y/ NN0170 X1.497 Y-.318 I-1.238 J.899* o; [) c0 |+ h6 w3 u
N0180 Y.318 I-1.497 J.318% L) t- L; ?, S/ s9 y3 Y; F+ X
N0190 X1.238 Y.899 J-.318
7 Y& @$ \) e9 K% JN0200 X.75 Y1.299 I-1.238 J-.899, I9 L4 z2 a9 N# _" m% N
N0210 X.16 Y1.522 I-.75 J-1.299
2 D- B( @3 o( F: s% p4 PN0220 X-.473 Y1.455 I-.16 J-1.522
3 z" Q% v6 D: w/ Q0 a% dN0230 X-1.024 Y1.137 I.473 J-1.4557 J6 Z& ` K8 I2 p
N0240 X-1.398 Y.622 I1.024 J-1.137 |
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