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本帖最后由 caiyingkai 于 2010-6-6 16:41 编辑 0 ~3 S2 P7 P6 S) t/ A1 T8 O7 F
D8 f, M8 m3 x" s: A处理出来的程式放机器上跑+Z超程?
9 K- t3 O4 j; c8 s5 C$ }5 z这程式怎么超程的?% y+ b0 c- g" o J+ j
发那科系统!* o' J8 f: Z! d+ j* Y, q
! Q, j; f! t# F* Q7 [) J( B如下1 {" C% ]( h3 t2 O7 `4 f7 C3 W5 @
N0010 G00 G40 G49 G17 G80 G90. a0 @* {" ?6 N" U
N0020 G91 G28 Z0.0
) ]/ \2 Q1 u) V0 ~4 JN0030 T01 M06% ]5 I' f8 k* a0 w. V3 }* n% m F
N0040 G00 G90 G54 X0.0 Y0.0
. p, n6 w0 \6 a" g, ]2 l3 _: e( `N0050 M08
0 \, F' ?2 J0 [# C S+ r4 v# JN0060 S1800 M03
: G0 Y# o9 N- O+ V" _. vN0070 G94 G00 G90 X-27.6 Y0.0 A315.
5 b7 c* j2 _& Z# LN0080 G43 Z37.5 H01
+ `6 J' n& d) }: Z! |N0090 Z24.+ q9 w4 t/ [7 P$ y e: S/ I
N0100 G01 Z21. F1000.0 N9 n, }5 H9 u5 \( T
N0110 X-10.
- k2 B& X- [+ t7 r! p" v1 BN0120 X10.$ f2 ]+ D1 ?! L9 M+ o7 L3 ~
N0130 Z37.
* K; K* r8 a5 sN0140 G00 X-27.60 c" ]8 x- y* [2 h. x2 r
N0150 Z23.5
5 m) f+ x \3 G+ h5 p# P% ?: t0 T# sN0160 G01 Z20.5
w( B% I' p H0 q pN0170 X-10.
0 P& `, G; d, [& K& c( ?3 _- HN0180 X10.1 q l; X) A, w6 {
N0190 Z36.5/ K2 P' D3 o4 {9 D* [
N0200 G00 X-27.6
+ P0 ?. H4 K2 r; I7 e+ Z2 I% j. fN0210 Z23.
# E1 k- @0 o( _N0220 G01 Z20.( F6 H/ e1 x- d/ T) `, t0 r
N0230 X-10.7 r! A5 b/ ^4 Y! a
N0240 X10.
% X. }6 w" Y6 M' v5 [' x5 tN0250 Z36.; A* ^; b, { ^3 r: U+ n
N0260 G00 Z37.5
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4 z7 \4 ?& x2 z% g还有就是出来一个报警020
% j! |/ I, { X3 i020 圆弧插补中,起始点和终点到圆心的距离的差大于876号参数指定的 % \$ \2 U1 T; M/ H$ `4 m, A5 M
数值。
0 ]9 }: V, ~) m; g' J/ Z+ }& \3 w9 g$ z
这个是什么意思呢!我的程式为+ i0 P( E; P) |8 m8 e% e
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N0080 G43 Z30.5 H06
* [( ^$ x# C( J8 l7 u3 YN0090 Z19.
+ H/ a3 \$ K( c; p% VN0100 G03 X-.459 Y-1.265 I.5 J0.0 F800.
, j( d8 o0 @+ uN0110 X-.265 Y-1.459 I.459 J.265
- {: U9 h ]1 _! J" r6 EN0120 X0.0 Y-1.5 I.265 J.459
) W2 R ]! ~, VN0130 X.266 Y-1.507 I0.0 J1.51 T) D" ~6 ^/ a( _
N0140 X.523 Y-1.438 I-.266 J1.507, m0 s C+ o' i" ]
N0150 X.75 Y-1.299 I-.523 J1.4383 I; o, K1 ?; y$ d( e
N0160 X1.238 Y-.899 I-.75 J1.299$ \% Z) h- m) K0 H
N0170 X1.497 Y-.318 I-1.238 J.899
0 T) A9 I! b2 R& nN0180 Y.318 I-1.497 J.318
- }: q3 l. F( `+ Z: F$ R! nN0190 X1.238 Y.899 J-.318
& e c0 V _* N4 B4 mN0200 X.75 Y1.299 I-1.238 J-.899
# G: m9 R, G% t3 x% D' hN0210 X.16 Y1.522 I-.75 J-1.299$ B: C5 ?) [! \! M4 n" ^
N0220 X-.473 Y1.455 I-.16 J-1.522 x, }4 Q# i' K1 ?$ z" |; x2 F6 r
N0230 X-1.024 Y1.137 I.473 J-1.455
; U, P8 G. ]5 L) k- L4 x! dN0240 X-1.398 Y.622 I1.024 J-1.137 |
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