拜求解决方案 | entity/ln1,ln2,ln3,ln4,ln5,ln6
: C6 }7 a& T) P4 O0 [% r9 centity/ps(6) % e5 R" h- F4 ], |
entity/cur(6) 4 v0 Q. z% \- K3 H5 K* |' V
entity/obj1,obj2,obj3
! b2 F, R: A R1 m1 Kentity/pt1,pt2,pt3,pt4,pt5 ( @4 M9 m! B6 W2 m L
entity/pl
7 h2 s9 N0 D) u1 [, v) @" n4 U3 qentity/grp # y4 r7 w$ q3 q3 I
l100:
. e2 d6 E2 B' k pt1=point/-2,0,1
) R+ p( n5 H$ r4 v" ~. V4 C pt2=point/-2,0,-1 - |7 Y: M( M* r0 _; U) h5 R
pt3=point/1.7,0,0
$ e2 z/ ~! w+ s8 }3 o N3 S pt4=point/-4,0,0
0 r8 Y" }1 R$ o. x5 Z. s ln1=line/pt1,pt3 6 X9 D! L/ V- q! l, w, @
ln2=line/pt2,pt3
/ v+ p+ b. E% F ln3=line/pt1,pt2
" J1 } r/ i! g% o7 x3 x4 Ul101:
+ {" m4 m& g5 O; V o cur(1)=line/parlel,ln1,zlarge,2 7 s# b3 h6 e) K, K
cur(2)=line/parlel,ln2,zsmall,2
5 [& H# Y/ {3 K0 }1 l cur(3)=line/pt4,parlel,ln3
F6 s7 M- r# m1 X0 S( P0 X* i+ Z# \ cur(4)=fillet/cur(3),cur(1),center,pt1,radius,2
% z; ^) j: }; { cur(5)=fillet/cur(2),cur(3),center,pt2,radius,2 + z. v8 n# g$ h. s5 g3 ~- U* ^
cur(6)=fillet/cur(1),cur(2),center,pt3,radius,2 ; g6 y: x2 f* J* i/ i. Z! G
grp=group/cur(1..6) 2 X) p8 \% O* L# N& t+ W
l102:
- m1 L% S+ x1 u: e+ n8 [7 V ps(1)=point/2,-5,0
! J. C" p( u6 ` K; U0 m ps(2)=point/2.3,-4,0
" v& Q/ D) H3 x: K/ Y7 W, u& Q ps(3)=point/2.7,-3,0
& k Q. _' g& T- F ps(4)=point/3.0,-2,0
! m, s l% o# ?9 z7 G ps(5)=point/3.4,-1,0 8 }/ ~7 o* G8 v1 j+ S
ps(6)=point/3.7,0,0
! s9 i) r( G1 {$ S7 t obj1=bcurve/ps(1..6),degree,3
- |, @9 a' F' P( ^2 \; {- r# ml103:
# I! G! n7 {, h5 z8 `; x8 q ln4=line/-4,0,0,-4,-5,0
2 c0 j( x- i2 _, Wl104:
, c2 ?4 i0 R1 a7 v; l. |* a1 M pt5=point/0,1,0
8 A) E, i+ M5 U& e+ r' W# ] ln5=line/pt5,atangl,45 , v. e& `" `& B0 O5 q' p
pl=plane/perpto,ln5,thru,ps(6) 3 R9 T3 `" ]7 v1 g7 Q" ]
l105: ( m4 C6 f% F( x R
obj2=solext/cur(1..6),height,4,axis,0,1,0 4 i: _% f' U$ W+ g1 p) H8 l
obj3=solcut/obj2,with,pl,cnt,c1,c2
6 u( U1 G' O) _" n8 i$ g8 jtrm:
9 C0 P$ u0 u) x2 g. }/ R" ]halt
' ^, B) U9 @* ~$ D我写的程序,我想通过曲线OBJ1和直线LN4导引曲面GRP,并将OBJ3其中的一部分删去 怎么做啊
* t+ J; i, e! j8 t6 q# i |
|