青华模具培训学校

 找回密码
 注册

QQ登录

只需一步,快速开始

青华模具培训学院
查看: 2191|回复: 2

程序贴上去,找人帮我改,谢谢

[复制链接]
发表于 2007-9-20 14:18 | 显示全部楼层 |阅读模式
拜求解决方案
entity/ln1,ln2,ln3,ln4,ln5,ln6 , j& y8 D9 j- M2 l$ z4 e
entity/ps(6)
% {' H4 m+ m5 Ientity/cur(6) * R' G& J1 U+ b/ j. n5 ^
entity/obj1,obj2,obj3
9 J. V1 U- E4 t, Y5 G+ s$ y4 ventity/pt1,pt2,pt3,pt4,pt5 ' ?/ |! C# z9 s. `* p
entity/pl $ I6 @# A% S! @; l- X
entity/grp
7 u% R8 c' ?. o' ml100: $ Y9 z6 [* L1 w
     pt1=point/-2,0,1 + }6 x* B- F/ m/ M9 V# P8 M* Q1 B" R# s
     pt2=point/-2,0,-1 & u; E% }6 _; E* u9 k
     pt3=point/1.7,0,0
% P  [0 E! `& u* L& e+ G6 a     pt4=point/-4,0,0 * |/ t0 D8 l% |7 g# ~( `& C  w
     ln1=line/pt1,pt3
$ f* ~! M5 i) Z% F- b* T: h     ln2=line/pt2,pt3 % K& {5 P$ Q# N* x# p. F
     ln3=line/pt1,pt2 " @# L! T; `8 v& e& n+ U
l101:
7 U# k" Y! C+ Y/ g% |; S1 n     cur(1)=line/parlel,ln1,zlarge,2 : E% d* b( b% o) f
     cur(2)=line/parlel,ln2,zsmall,2
5 y( O. n# q8 q( P$ b0 K, `0 }     cur(3)=line/pt4,parlel,ln3 : I4 K/ R" c7 {4 o) J% q
     cur(4)=fillet/cur(3),cur(1),center,pt1,radius,2
8 q8 F% i7 X, m     cur(5)=fillet/cur(2),cur(3),center,pt2,radius,2
" M  T0 V6 E3 r     cur(6)=fillet/cur(1),cur(2),center,pt3,radius,2
2 s- _1 e  D+ K' O3 i     grp=group/cur(1..6) . B+ z5 I  r" P8 f" {6 a
l102:
% n2 c, s  S: e) b' g$ i/ L, Q     ps(1)=point/2,-5,0 % S4 r, e$ I1 o# M6 v* v
     ps(2)=point/2.3,-4,0
* z. Z4 i, ?# ?9 z1 m3 `     ps(3)=point/2.7,-3,0 0 ^* Q! [2 }0 q" ]/ R6 V* N
     ps(4)=point/3.0,-2,0
" f# N3 m% ^- ^4 r     ps(5)=point/3.4,-1,0 , q5 W: z6 e# h: O- ]2 C4 [
     ps(6)=point/3.7,0,0   t/ _. W3 T2 @3 |; _* s& K
     obj1=bcurve/ps(1..6),degree,3
: v! x5 S$ B4 t4 el103: 1 b( O0 Y5 d$ r* y0 {
     ln4=line/-4,0,0,-4,-5,0
, @$ N: a* x2 [7 Ol104: % M  Q6 i1 R4 g# x. h* L& i
     pt5=point/0,1,0 * M: {* y3 M6 y/ q  x6 h
     ln5=line/pt5,atangl,45 # I; J& D6 }* H( R# [5 e
     pl=plane/perpto,ln5,thru,ps(6) 3 H7 Q3 L8 w; O  K' t1 j+ n1 U
l105: - f. o: g& ]# w" l0 t
     obj2=solext/cur(1..6),height,4,axis,0,1,0
: U- S* ^+ P4 `$ ^# v! x     obj3=solcut/obj2,with,pl,cnt,c1,c2
$ n! i6 v4 m) \trm: ; g7 R3 G0 S; B7 H9 q
halt / K2 H" N* s# h% ~$ I6 _. z
我写的程序,我想通过曲线OBJ1和直线LN4导引曲面GRP,并将OBJ3其中的一部分删去 怎么做啊
6 Z8 h/ j9 x$ z. {- ~& e% l( f
发表于 2007-9-21 09:38 | 显示全部楼层
entity/ln(6),ps(6),cur(6),obj(3),pt(5),pl,grp,TE(10)& a! y3 [, V0 {0 L3 e

* a: O0 U/ }  ~/ y- l
- H; F! q# g$ _5 m7 v% }( ^     pt(1)=point/-2,0,1
- i( @- Q/ r; E9 M. I/ {  o6 l: y3 e     pt(2)=point/-2,0,-1
1 v' T$ }1 l7 J5 M     pt(3)=point/1.7,0,0
3 v8 z# Q* c- S$ ~  U     pt(4)=point/-4,0,0
: a+ @( U1 H% a) E     ln(1)=line/pt(1),pt(3) * w0 P4 M. g7 e$ \0 k' r
     ln(2)=line/pt(2),pt(3)
' W+ V' k% [4 F     ln(3)=line/pt(1),pt(2)
- ~4 C( z( [# M; o; ^" v' w) L
4 O. S4 E% _/ W. ?
5 k. @/ x% ?! w& n1 m     cur(1)=line/parlel,ln(1),zlarge,2
0 }$ u( q7 J7 a5 |/ v     cur(2)=line/parlel,ln(2),zsmall,2 $ Q5 M' d! u- \0 R/ X
     cur(3)=line/pt(4),parlel,ln(3)
% w" Q+ i* D( h; ^* x     cur(4)=fillet/cur(3),cur(1),center,pt(1),radius,2 % G* b4 R0 H/ z# R1 o# L: _# S
     cur(5)=fillet/cur(2),cur(3),center,pt(2),radius,2
. _% g: q+ H* e0 R4 C; D$ T, `& a     cur(6)=fillet/cur(1),cur(2),center,pt(3),radius,2
! P6 k, K  e6 a     grp=group/cur(1..6) ) V! {: c& W, A6 A$ G
) p0 y& o  R1 t2 m& f
     ps(1)=point/2,-5,0
# e; k. o1 }; R# `* X     ps(2)=point/2.3,-4,0 ! K6 T- H) o6 v2 w& W7 |' X
     ps(3)=point/2.7,-3,0
: ?7 i/ i" z1 g/ a     ps(4)=point/3.0,-2,0
2 I; k' k' |$ H7 ?7 e" m7 S2 F3 ~     ps(5)=point/3.4,-1,0
# Q2 }+ U8 B7 C* `( t     ps(6)=point/3.7,0,0
# V4 w/ V' x. U, b; B6 E     obj(1)=bcurve/ps(1..6),degree,3 + e/ j0 v3 S7 m3 c

: r& s2 G- q' r! u. Z, \   ]# a2 F" Z2 {* \4 E. J
     ln(4)=line/-4,0,0,-4,-5,0
+ Y" {! r0 l/ a# l - }0 e7 O0 G' {) J
     pt(5)=point/0,1,0 - P. q: @' O+ k4 p0 z7 x4 \8 N" n
     ln(5)=line/pt(5),atangl,45
) ]+ y, ~9 c! U; r     pl=plane/perpto,ln(5),thru,ps(6) , \$ Y9 x1 o& e( P& K
" A+ c# p% f2 I6 f! M  R9 ?% Z$ s

  B8 ~% ~' ]( ?2 ]" F; K+ n& j     obj(2)=solext/cur(1..6),height,4,axis,0,1,0 ; S* W7 ]( d/ M2 o% }0 l- e/ G5 @- x8 w
- V4 _2 s- [& a
     obj(3)=solcut/obj(2),with,pl,cnt,NUM,c2 , o+ @* c/ E7 V  U9 C
1 G6 [7 i% R9 W  n% M, r. I" U
- W" B8 }& d& v* h
    MASK/70
8 B5 n- _- D# i& ~& C' p. zl100:1 k7 z; D+ g, @# E: p, L
    DO/DOL90:,I,1,NUM
* r/ m- N- k, ?" y1 `        TE(I) = NEXTE/IFEND,L200:$ R& u, U  W$ G7 F+ x" @5 u
    DOL90:& e! K7 C4 b2 S6 V
L200:+ t+ t% Z$ Y7 u+ }3 `
        DELETE/TE(I)/ K. m0 Y: t' u! d/ N7 ~

+ J; N' E6 @1 T/ E8 Dtrm: 0 d0 T& N( r9 c6 V% g
halt

评分

参与人数 1流量 +5 技术 +1 G币 +1 收起 理由
xcb + 5 + 1 + 1 技术解答

查看全部评分

 楼主| 发表于 2007-9-21 10:20 | 显示全部楼层

还有一部分要请教

在我的程序中间不是有一个GRP吗??我想通过obj1和ln4导引,通过扫略形成实体,我试过N多次都不成功,不知道试为什么??
9 R7 u1 u9 P/ X3 D4 d* I还有我想了解一下你,你是做什么工作的,你对UG好像很了解,以后向你多多学习
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|关于我们|sitemap|小黑屋|Archiver|手机版|UG网-UG技术论坛-青华数控模具培训学校 ( 粤ICP备15108561号 )

GMT+8, 2025-2-19 06:15 , Processed in 0.055898 second(s), 28 queries .

Powered by Discuz! X3.5 Licensed

© 2001-2024 Discuz! Team.

快速回复 返回顶部 返回列表