青华模具培训学校

 找回密码
 注册

QQ登录

只需一步,快速开始

青华模具培训学院
查看: 2077|回复: 2

程序贴上去,找人帮我改,谢谢

[复制链接]
发表于 2007-9-20 14:18 | 显示全部楼层 |阅读模式
拜求解决方案
entity/ln1,ln2,ln3,ln4,ln5,ln6
: C6 }7 a& T) P4 O0 [% r9 centity/ps(6) % e5 R" h- F4 ], |
entity/cur(6) 4 v0 Q. z% \- K3 H5 K* |' V
entity/obj1,obj2,obj3
! b2 F, R: A  R1 m1 Kentity/pt1,pt2,pt3,pt4,pt5 ( @4 M9 m! B6 W2 m  L
entity/pl
7 h2 s9 N0 D) u1 [, v) @" n4 U3 qentity/grp # y4 r7 w$ q3 q3 I
l100:
. e2 d6 E2 B' k     pt1=point/-2,0,1
) R+ p( n5 H$ r4 v" ~. V4 C     pt2=point/-2,0,-1 - |7 Y: M( M* r0 _; U) h5 R
     pt3=point/1.7,0,0
$ e2 z/ ~! w+ s8 }3 o  N3 S     pt4=point/-4,0,0
0 r8 Y" }1 R$ o. x5 Z. s     ln1=line/pt1,pt3 6 X9 D! L/ V- q! l, w, @
     ln2=line/pt2,pt3
/ v+ p+ b. E% F     ln3=line/pt1,pt2
" J1 }  r/ i! g% o7 x3 x4 Ul101:
+ {" m4 m& g5 O; V  o     cur(1)=line/parlel,ln1,zlarge,2 7 s# b3 h6 e) K, K
     cur(2)=line/parlel,ln2,zsmall,2
5 [& H# Y/ {3 K0 }1 l     cur(3)=line/pt4,parlel,ln3
  F6 s7 M- r# m1 X0 S( P0 X* i+ Z# \     cur(4)=fillet/cur(3),cur(1),center,pt1,radius,2
% z; ^) j: }; {     cur(5)=fillet/cur(2),cur(3),center,pt2,radius,2 + z. v8 n# g$ h. s5 g3 ~- U* ^
     cur(6)=fillet/cur(1),cur(2),center,pt3,radius,2 ; g6 y: x2 f* J* i/ i. Z! G
     grp=group/cur(1..6) 2 X) p8 \% O* L# N& t+ W
l102:
- m1 L% S+ x1 u: e+ n8 [7 V     ps(1)=point/2,-5,0
! J. C" p( u6 `  K; U0 m     ps(2)=point/2.3,-4,0
" v& Q/ D) H3 x: K/ Y7 W, u& Q     ps(3)=point/2.7,-3,0
& k  Q. _' g& T- F     ps(4)=point/3.0,-2,0
! m, s  l% o# ?9 z7 G     ps(5)=point/3.4,-1,0 8 }/ ~7 o* G8 v1 j+ S
     ps(6)=point/3.7,0,0
! s9 i) r( G1 {$ S7 t     obj1=bcurve/ps(1..6),degree,3
- |, @9 a' F' P( ^2 \; {- r# ml103:
# I! G! n7 {, h5 z8 `; x8 q     ln4=line/-4,0,0,-4,-5,0
2 c0 j( x- i2 _, Wl104:
, c2 ?4 i0 R1 a7 v; l. |* a1 M     pt5=point/0,1,0
8 A) E, i+ M5 U& e+ r' W# ]     ln5=line/pt5,atangl,45 , v. e& `" `& B0 O5 q' p
     pl=plane/perpto,ln5,thru,ps(6) 3 R9 T3 `" ]7 v1 g7 Q" ]
l105: ( m4 C6 f% F( x  R
     obj2=solext/cur(1..6),height,4,axis,0,1,0 4 i: _% f' U$ W+ g1 p) H8 l
     obj3=solcut/obj2,with,pl,cnt,c1,c2
6 u( U1 G' O) _" n8 i$ g8 jtrm:
9 C0 P$ u0 u) x2 g. }/ R" ]halt
' ^, B) U9 @* ~$ D我写的程序,我想通过曲线OBJ1和直线LN4导引曲面GRP,并将OBJ3其中的一部分删去 怎么做啊
* t+ J; i, e! j8 t6 q# i
发表于 2007-9-21 09:38 | 显示全部楼层
entity/ln(6),ps(6),cur(6),obj(3),pt(5),pl,grp,TE(10)
  r% _# F$ |2 `$ W2 s
( t2 y( B# v/ l3 L9 A: l1 H0 H$ F" }1 G. h
     pt(1)=point/-2,0,1 3 i7 i" _4 \$ Z& Y' k
     pt(2)=point/-2,0,-1 # M: |0 s7 d) E
     pt(3)=point/1.7,0,0
/ w' O; d" V6 w5 c, Z     pt(4)=point/-4,0,0
) H) ^: \1 ~1 R     ln(1)=line/pt(1),pt(3) ' W* y& Y$ g+ U; D6 [
     ln(2)=line/pt(2),pt(3)& m# i  ?: B) p8 u* r+ l% s
     ln(3)=line/pt(1),pt(2)- D4 h" F3 H' v9 B4 j$ F
: z9 E4 g2 O* v% F( X6 v

6 H2 Z9 u" `  O. |* |" F6 Y     cur(1)=line/parlel,ln(1),zlarge,2
+ G" i4 ]/ A& r5 ]' [5 V- o     cur(2)=line/parlel,ln(2),zsmall,2 5 G1 j  I( p& g
     cur(3)=line/pt(4),parlel,ln(3) % T" ?) p( _6 C2 b; L) s
     cur(4)=fillet/cur(3),cur(1),center,pt(1),radius,2 5 p5 a  Q: R, e* g1 [1 h" N+ v4 Q/ ]  @
     cur(5)=fillet/cur(2),cur(3),center,pt(2),radius,2 * D1 @! q" v1 W. ?. g% Q
     cur(6)=fillet/cur(1),cur(2),center,pt(3),radius,2 7 U8 D' u( Z6 Z( Y1 H% F
     grp=group/cur(1..6) : N$ q2 `; `  L! g+ ]0 K

+ A( T+ }/ Q1 x+ o     ps(1)=point/2,-5,0
. h- r) Z6 j( e7 Q. M& ?% O     ps(2)=point/2.3,-4,0
4 D9 Y) k+ @! q! J2 s" Q" ]4 M     ps(3)=point/2.7,-3,0
1 D- V  Y; B2 Z% Q1 h' B     ps(4)=point/3.0,-2,0
- e3 c6 V) \- O7 Z: B     ps(5)=point/3.4,-1,0 2 L/ T$ l1 p+ T1 I6 \1 A1 N7 ~$ c
     ps(6)=point/3.7,0,0
# c  R) k, `0 O) h, Z# L     obj(1)=bcurve/ps(1..6),degree,3
- \9 k+ i7 \7 a" R8 p+ P
# w0 o& |8 ?- A2 w7 l% x : c: G# w- ^3 S4 f
     ln(4)=line/-4,0,0,-4,-5,0 / Y* m* d# n! k* x& ?4 j8 o
: c+ L" J+ ?8 Y7 D' M/ o5 d
     pt(5)=point/0,1,0
) E  ?) z6 ~) R     ln(5)=line/pt(5),atangl,45
) I' t6 D8 Y5 J2 O. g     pl=plane/perpto,ln(5),thru,ps(6) + ?  s5 K' k1 v6 b  O

9 q9 d3 i1 O8 O4 R
0 Q% H! Q) O$ D( u# V6 a0 N( S/ d! q     obj(2)=solext/cur(1..6),height,4,axis,0,1,0 ( L, `  q- a8 ^9 Q7 |1 L
3 \/ B: B6 c! u8 s( R7 T  i. p
     obj(3)=solcut/obj(2),with,pl,cnt,NUM,c2 8 e4 U# u) k- L6 x) W
3 l. G  b3 B+ }

7 E! [- \, C# K! j% S    MASK/70
9 W. P3 z, f2 nl100:
( k, s/ Z& H% B; i    DO/DOL90:,I,1,NUM
9 t/ J8 X0 T1 `4 b' [- `        TE(I) = NEXTE/IFEND,L200:" V" J6 j$ U& d; E7 z7 s
    DOL90:" s1 P9 p1 S  ]
L200:2 O  b/ p3 H2 C. F- S
        DELETE/TE(I)
  e& P8 L  O) W& `2 P/ ?, t' v
% C' f+ S/ ]2 O: Q9 F2 N/ X  ?( V: Btrm: 7 [. g2 c4 h3 C% H
halt

评分

参与人数 1流量 +5 技术 +1 G币 +1 收起 理由
xcb + 5 + 1 + 1 技术解答

查看全部评分

 楼主| 发表于 2007-9-21 10:20 | 显示全部楼层

还有一部分要请教

在我的程序中间不是有一个GRP吗??我想通过obj1和ln4导引,通过扫略形成实体,我试过N多次都不成功,不知道试为什么??
6 ^* ^4 s  o2 d0 p& b0 w. e还有我想了解一下你,你是做什么工作的,你对UG好像很了解,以后向你多多学习
您需要登录后才可以回帖 登录 | 注册

本版积分规则

QQ|关于我们|sitemap|小黑屋|Archiver|手机版|UG网-UG技术论坛-青华数控模具培训学校 ( 粤ICP备15108561号 )

GMT+8, 2024-4-28 19:56 , Processed in 0.060129 second(s), 25 queries .

Powered by Discuz! X3.5 Licensed

© 2001-2023 Discuz! Team.

快速回复 返回顶部 返回列表