拜求解决方案 | entity/ln1,ln2,ln3,ln4,ln5,ln6 - ~0 c# t* `& m, R7 @
entity/ps(6) V( L) M; A4 b, n) l+ f
entity/cur(6) 0 l4 n5 g. a& z" N0 A
entity/obj1,obj2,obj3
1 h$ q1 O! D4 A: n2 l+ g' V: l; q5 xentity/pt1,pt2,pt3,pt4,pt5
& d, G/ a0 c/ Y: v6 ]3 _. H; A" sentity/pl
- u1 q$ ]! t& J' b! t& ?entity/grp . x, v W0 u- i8 l
l100:
3 @! ~' A1 A- O3 o9 |5 g pt1=point/-2,0,1 6 Y i! @! r0 \) P; I; W
pt2=point/-2,0,-1 / A5 ], T4 e9 E& a" |; D7 z" r( L
pt3=point/1.7,0,0 - h, a& O; P5 k) C, [
pt4=point/-4,0,0
1 f7 v6 l. x0 L0 s% V ln1=line/pt1,pt3
6 Q0 B9 [- i/ U. T5 R! ^ ln2=line/pt2,pt3
& _, |# ]& g; L ln3=line/pt1,pt2 ! L$ L. G2 p% M+ x& a
l101:
& T! J: e! }. M+ N cur(1)=line/parlel,ln1,zlarge,2 + P" d/ Q8 F @
cur(2)=line/parlel,ln2,zsmall,2
! ~( [6 [. D# T( {2 B: l cur(3)=line/pt4,parlel,ln3
( Y- G% Q% k- t. i cur(4)=fillet/cur(3),cur(1),center,pt1,radius,2
1 X$ i* ~: v0 T) d$ N/ k! F6 n cur(5)=fillet/cur(2),cur(3),center,pt2,radius,2 ! c* C4 _' U4 F/ p1 _+ a8 T
cur(6)=fillet/cur(1),cur(2),center,pt3,radius,2 5 C6 c' g) ~& `3 ]
grp=group/cur(1..6) , F' m- h5 J6 I5 \2 ]
l102: % D" E6 [# c& I) }! B$ |; m
ps(1)=point/2,-5,0
/ \$ X9 N2 t7 X" d0 P: v ps(2)=point/2.3,-4,0 " m [, n; G! [7 _" N
ps(3)=point/2.7,-3,0 $ x/ F& o2 B. A, }, D: |
ps(4)=point/3.0,-2,0 + |) F7 H$ r& D: Z6 ]3 x& t) U
ps(5)=point/3.4,-1,0
/ M4 Y1 s) K8 D& e& J5 ] ps(6)=point/3.7,0,0 + ^/ Y7 U. F4 S5 @( _
obj1=bcurve/ps(1..6),degree,3
, A+ Z' S6 M8 y% |l103:
, L% i" i$ E) I0 G2 B' y4 D ln4=line/-4,0,0,-4,-5,0 ! c. g( g1 Y2 i+ o+ r8 y6 \
l104: 8 o2 i, X7 d6 X' K/ P$ O8 E
pt5=point/0,1,0 ; f' M3 w7 O+ T! \' E
ln5=line/pt5,atangl,45 5 s- b1 @; Q- ?8 r
pl=plane/perpto,ln5,thru,ps(6)
) ], l, q1 `0 q# X7 l% dl105:
3 t q' P! ^4 f* L$ H! |: N obj2=solext/cur(1..6),height,4,axis,0,1,0
( l6 j7 a" R C6 s$ q obj3=solcut/obj2,with,pl,cnt,c1,c2
$ E+ N1 R2 S( N% v' }4 h! Vtrm:
) `! r# e" K3 h$ I" Lhalt
9 |9 s5 Y% o1 @) }我写的程序,我想通过曲线OBJ1和直线LN4导引曲面GRP,并将OBJ3其中的一部分删去 怎么做啊
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