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如题, 怎么我的后处理出的程序只有开始的G1 有F值,到后面的G0 走过之后再来个G1或者G2 G3 它就都没F 我的是8。08 N! \* j ]. s/ J' u5 I/ z5 h; A
就向下面的这样$ q$ R, V# _5 x8 M! b: w! d
%
/ p( S3 M) ~6 X- I& z% B(NAME :MILL )
2 K) v3 |$ w4 z; _(D : 16.00 )( j/ K- Q" z7 ^4 j2 D
(R :?0.80 )
( N7 t- G1 Y) s0 O( N2 UN0001 G40 G17 G90 G21 G80$ s7 T8 N) W( x4 V! Q. l) z
N0002 G91 G28 Z0.0
. I9 V" K! X6 Y. V2 @( oN0003 T01 M06
( V8 i9 ~9 q# x& N- }& cN0004 G00 G90 G54 X2.475 Y.033 S2500 M03
9 Q4 j9 }$ E' M3 b# JN0005 G43 Z100. H013 u( |5 D A( ]# _/ _1 U2 J
N0006 Z2.5
8 {: V+ K2 U! `. T# {$ qN0007 G01 Z-.5 F2000. M082 o1 |) `( t B
N0008 G03 X0.0 Y1.058 I-2.475 J-2.475
( ]- |4 \. m' d# {1 bN0009 G01 X-11.058: W: ?4 F) Y2 R
N0010 Y-1.058: a4 c& B$ T" w3 W
N0011 X11.058
, {8 O+ g+ g0 q8 VN0012 Y1.058
1 j0 i Q2 ~! T5 F3 o7 {N0013 X0.06 m% v8 j- D8 V- O, n' b
N0014 G03 X-2.475 Y.033 I0.0 J-3.5
+ C0 t3 h8 s5 f, [0 k4 @N0015 G01 Z2.50 `) a4 k) F" u1 i
N0016 G00 G54 X2.475 Y-.025
: U. T- y9 Y' M& z# Z2 tN0017 Z2.$ \9 ` h3 X3 c, \
N0018 G01 Z-1.
$ b( _/ b. v2 I% _/ G5 V4 }3 hN0019 G03 X0.0 Y1. I-2.475 J-2.475- z, C9 a+ ]5 ?) E0 I
N0020 G01 X-11.
$ T: a* z7 A( qN0021 Y-1.7 [- G' P# K2 Q$ ]* R, m6 ^* r
N0022 X11.
4 f* A4 l& D& L( C6 z; pN0023 Y1.6 I5 J: I, x% p8 @: U
N0024 X0.0
5 o# ?9 F: N3 v" k6 S# s& R' C. KN0025 G03 X-2.475 Y-.025 I0.0 J-3.5
: W9 ?1 p9 E# K; S- XN0026 G01 Z2.+ i4 M: M6 d1 _) W( `8 m6 {6 q0 X
N0027 G00 G54 X2.4752 v( u/ B _2 `$ {1 C: u5 ~
N0028 Z1.5( M5 C( G; L) J& z; D/ D
N0029 G01 Z-1.5
! r `' j q8 l! Q. K+ j- AN0030 G03 X0.0 Y1. I-2.475 J-2.475
! ^, e4 a+ q. J# xN0031 G01 X-11. n5 X S, d) s1 l9 f# ~, l
N0032 Y-1.
" ~1 r4 M6 k4 [/ @8 L4 }( tN0033 X11.: Y2 h; f$ L8 Z, a4 l% h: S: }) l, f
N0034 Y1.
. M$ J: y0 ^7 J8 E1 ]* _2 hN0035 X0.0
- f+ @; k1 h7 C# i2 x0 `N0036 G03 X-2.475 Y-.025 I0.0 J-3.52 A" B, h }8 w/ r2 |. x
# Y1 E' B3 F' E L1 C
* U, J2 ?0 P' t1 D" a补充内容 (2012-5-27 12:13):0 k9 I6 p: f. p) u+ ^4 T
问题已经解决其实只要点击一下逼近移动就好了
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