本帖最后由 bee 于 2015-12-15 12:47 编辑
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可分别设定两个或其中一个齿轮“齿数”而自动改变的斜齿轮组/ I7 {, e; G3 {2 X4 p, D
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但画出来的样子跟“外挂”出来的差了3C左右,不知道是否能用!!/ h6 M4 ~+ B% P) S$ [) _' J
有实体图ug/NX10.0格式,想要的会员可留言QQ号 _) g! {. J+ @# A4 C' p
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UG表达式:
! T8 z1 b. b; T. K[degrees]Alpha="Helical_Gear"::Alpha, \8 i8 ?- L7 `5 R( J
Beta=p107
& K8 ^- c; @* Q& v& C- T& @' X/ V4 C1 uH=p111
6 }9 S) _- [0 x, D5 J( E) N5 W[mm]Hole=if(df<20)(Hole_c)else(ceiling(ceiling(df/10)*10/3))
* n+ E5 j1 J6 F# I; g. f: |[mm]Hole_c=ceiling(ceiling(df)/2)
z2 l8 s% \5 W4 }8 n8 N[degrees]a=180/z
) @" [) d, g5 m {. [[degrees]a1=-(a+2*bk)4 B" n4 s; m6 s5 s
[degrees]ak=Alpha8 V9 ~! @$ `4 |3 i/ R
ak1=arccos(db/da), d8 z( z2 V$ u# y
[degrees]ak2=deg(ak1)! }; w4 v, s6 Z3 b" u$ F$ D8 J
[degrees]bk=deg(tan(ak)-Radians(ak))+ e, S9 J+ ]1 T7 F7 e( _ e, f
bk1=tan(ak1)-ak1, F; S- k$ l8 _; j s' J
[degrees]bk2=deg(bk1)4 e8 Q0 g0 M9 H
[mm]c=0.25
" ?- ?2 Q1 m J- U# `[mm]d=(m/cos(Beta))*z! o, E8 |. s+ c: {2 {4 i
[mm]da=d+2*ha*m
2 E. [& d, L! |! k$ o2 k$ S[mm]db=d*cos(ak)0 ]; n; c, S" w. B8 a* P% B1 w
[mm]df=d-2*m*(ha+c)
+ R9 g4 Z1 D7 R1 Y5 U/ H* K4 kft_2=-t*((tan(Beta)*H*360)/(d*pi()))
2 k- f s$ H; e4 |+ J0 K[mm]ha=19 F; v0 V0 K7 Y4 z
m=1; D2 S; E* t' t: }* A+ r3 Z
n=34 u, E$ W# X G- x5 L3 S/ D
nm="Helical_Gear"::nm
$ X. O5 P5 p5 e# B3 z3 i% b6 e1 o! kp7=2( J2 Y' v$ [% I# W. ^
[degrees]p8=a1
5 l$ c0 P$ g5 `- J: X/ y[mm]p9=10
0 I$ f9 O$ M9 |; Y+ ~[degrees]p10=-21.415833167365
% d- x! c7 M4 W; j: k' U" ~, m& [[mm]ra=da/2+ P) g, R4 d8 g( E! F) i
[mm]rb=db/2
0 U$ W# O) h/ Bt=1
) I+ G- H& j2 a5 C+ J( Vu=ak2+bk2
5 `) r5 Y6 r& \# ?3 l6 X. t4 {u1=Radians(u)# O7 w5 G9 v( A$ m( }" ^
[mm]x1t=-(rb*sin(u*t)-rb*u1*t*cos(u*t))
. U+ S! b1 _$ V# l' E2 H[mm]xt=rb*sin(u*t)-rb*u1*t*cos(u*t)% t, V( b! X- v3 R# ?6 k3 P' B
[mm]yt=rb*cos(u*t)+rb*u1*t*sin(u*t)1 g; G+ B: G" ?9 z
z=z1
/ ?7 v0 G% d, l& [& U4 j1 B& _z1="Helical_Gear"::z12 d6 D/ S- [" i8 V( ~
[mm]zt=01 C( b9 \3 ], k% T! d- M
p11=2' g1 }; u% V/ q7 r9 n
[mm]p12=10; v7 p# D4 ~" D0 o
[mm]p13=10
9 D+ i0 f4 d% F/ e& {4 t" W[degrees]p14=03 M) [- M4 W8 s/ I+ k( A! {2 S8 R
[mm]p15=d
" U! e4 L; n$ J6 U0 t& b( _3 _[mm]p16=df
) ]- ]% B8 |$ M# k! c( J- n[mm]p17=H, p; U" T" R* J' I- n
[mm]p18=H% [! J- ~- O. b7 H5 P6 W3 H" Q
[mm]p18_x=0.000000000001 Q9 c2 n. J% c) O: V. l- ~3 P
[mm]p19_y=0.000000000008 |5 f: [) J. ^ \# S
[mm]p20_z=0.00000000000
8 G/ J) i; @7 r0 x, g[mm]p36=da+ v D4 B. G; V( \ v5 ^# |- @
[mm]p37=H3 G' A) v7 e( M- z0 O; u; C
p45=z
5 F4 T/ c8 ^$ I* Y6 K/ x[degrees]p46=360/z( G( Q4 W# {& L0 u; x/ P
[mm]p47=10
. X$ }% O/ [( z$ P5 G[degrees]p48=360( B/ Q6 b) Z+ b
p49=1
" l/ _9 Z+ ^% [& U+ H3 p[mm]p50=106 t( a5 s+ E6 o( X; ^: e
[mm]p51=08 `0 {# B5 }# Y% y
[degrees]p52=0) d: g; ?1 x( u5 D9 I- o! J/ A
[mm]p56_x=0.00000000000
p& z B) x1 h2 g[mm]p57_y=0.00000000000
: O; }) J0 p* ][mm]p58_z=0.00000000000
4 f; Q% F$ b: F+ L' T[mm]p94_x=0.00000000000
' ~: ?- t0 N/ I1 `) s$ L[mm]p95=Hole
W/ @/ S, \( g/ [[mm]p95_y=0.00000000000, L- `& r5 Z5 l& i, i1 Q
[mm]p96=H
$ i$ }1 u8 y& ?8 S9 v/ ]1 c[mm]p96_z=0.00000000000
4 M2 f" ?* e# F0 J% u[mm]p104=c2 ~" y" j' h8 |
p107="Helical_Gear"::Beta
- z! a: d8 g, O, m$ r8 |p111="Helical_Gear"::H1 I, C9 E3 u( ]0 T) Z
[mm]p112=ceiling(p113/3)8 g) h! Q$ e; Y' u
[mm]p113=ceiling(Hole/4)) Q1 S" X* }% h/ q
[mm]p114=0
$ I3 ~+ |& G6 H/ e; }[mm]p115=H2 I5 D" J$ a W$ Y* x8 J! N
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