关于布尔运算UF_MODL_unite_bodies_with_retained_options

a0806

#include <uf.h>
+ l# J% {# X* k5 }* B9 k$ [#include <uf_ui.h>
#include <uf_exit.h>
#include "uf_modl.h"
extern DllExport void ufusr( char *parm, int *returnCode, int rlen )
! v$ k! T' g9 T& a{
, u# W6 y; r5 v% u/ K0 g    /* Initialize the API environment */
' L/ }& x# ~5 N7 p9 i3 s0 Z# @    if( UF_initialize() )
* e) [9 K  q$ |2 u; s    {
        /* Failed to initialize */
        return;
- a. o2 i% S& l. S; h. A) O8 @% J    }
$ I( p9 y8 B: c* G3 m" N UF_FEATURE_SIGN sign = UF_NULLSIGN;
: l8 B/ [& s5 d% u, Q double origin[3] = {0,0,0};
9 ~* F: ~/ H; E char* height = "5";
char* diam = "8";
double direction[3] = {0,0,5};
% N7 z' p3 }. Y tag_t cyl1;
UF_MODL_create_cyl1(sign,origin,height,diam,direction,&cyl1);
6 c' s6 a, g$ o char* height2 = "50";
: o' |+ k( H$ p: q% g8 }1 E2 H& k char* diam2 = "4";
6 g! r0 y5 j) H$ A6 t tag_t cyl2;
UF_MODL_create_cyl1(sign,origin,height2,diam2,direction,&cyl2);
tag_t cyl_ent;
logical retain_target_body=FALSE;
logical retain_tool_body=FALSE;
. [& G/ ]0 J% w+ }1 ^; i/ q& i UF_MODL_unite_bodies_with_retained_options (cyl1,cyl2,retain_target_body,retain_tool_body,&cyl_ent);
  d' G9 q; F5 X    /* Terminate the API environment */
3 K' i+ ~- F1 B: x7 A, s- N2 j    UF_terminate();
# A7 J+ h) C% m3 T4 |- v! K9 {: ~7 d. \}
2 O- e! Y0 a3 U2 L. O
extern int ufusr_ask_unload( void )
{
: B( ~6 Z5 f" A, x* D" \& `    return( UF_UNLOAD_IMMEDIATELY );
* I# Z* k3 h3 ~9 c7 w7 F/ {5 h}
( I  V7 t3 f# z2 p5 m, W
8 q5 P4 t( l- X# z* W( K

a0806

但是把两个没有没有参数的实体,进行遍历选中,是可以进行布尔的,
# v$ G5 d0 }+ K! `不知道什么原因,
请大侠们 指点

t124113

做为一名UG爱好者，看帖看完了至少要顶一下，还可以加入到淘帖哦！

a0806

搞定了
0 C- n2 ~; C5 e
" ?: ?* n/ T0 l                        UF_MODL_ask_feat_body(cyl_jt1,&cyl_jt1);  //从特征feature中取出body
                        UF_MODL_unite_bodies(cyl_jt1,cyl_jt2);  //布尔运算,求和
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