关于布尔运算UF_MODL_unite_bodies_with_retained_options

a0806

#include <uf.h>
#include <uf_ui.h>
$ E# s- L  S9 G. ~$ ~: E# n#include <uf_exit.h>
#include "uf_modl.h"
extern DllExport void ufusr( char *parm, int *returnCode, int rlen )
{
2 q; |  A+ Q" X$ M+ C* `/ F    /* Initialize the API environment */
  g0 g  I! D% A( F3 P6 h    if( UF_initialize() )
    {
3 f4 g5 R* X6 T        /* Failed to initialize */
6 |3 M: J  h- U6 |2 M        return;
+ L9 n+ K% `" @% P) J: C# m  f    }
UF_FEATURE_SIGN sign = UF_NULLSIGN;
double origin[3] = {0,0,0};
char* height = "5";
char* diam = "8";
double direction[3] = {0,0,5};
tag_t cyl1;
UF_MODL_create_cyl1(sign,origin,height,diam,direction,&cyl1);
' @3 p* K: U. X3 h0 S% B2 \ char* height2 = "50";
4 `9 Y; r$ [+ g6 G% O, a char* diam2 = "4";
tag_t cyl2;
: `* M3 N; d) P% ^% I; _/ q UF_MODL_create_cyl1(sign,origin,height2,diam2,direction,&cyl2);
tag_t cyl_ent;
1 m; l% x3 y, r logical retain_target_body=FALSE;
( I! }2 H+ B" J9 [* k9 c logical retain_tool_body=FALSE;
1 ?0 x  M% ^8 I9 ?( { UF_MODL_unite_bodies_with_retained_options (cyl1,cyl2,retain_target_body,retain_tool_body,&cyl_ent);
  a3 R; X$ x+ Y) c    /* Terminate the API environment */
! |$ {( B# ]$ g8 X; `$ F7 l    UF_terminate();
- g  g( q% n% T; f. w+ b+ @# \) T}

extern int ufusr_ask_unload( void )
: c+ e6 S3 h, k% Z! `{
; H$ {" H2 u  g0 e8 h1 t2 J% \    return( UF_UNLOAD_IMMEDIATELY );
, R; h; E. t- K}
9 O; @2 j% J$ F$ y2 q: R+ t7 G

a0806

但是把两个没有没有参数的实体,进行遍历选中,是可以进行布尔的,
不知道什么原因,
请大侠们 指点

t124113

做为一名UG爱好者，看帖看完了至少要顶一下，还可以加入到淘帖哦！

a0806

搞定了

                        UF_MODL_ask_feat_body(cyl_jt1,&cyl_jt1);  //从特征feature中取出body
* S+ g, t# N; i0 {" a& i                        UF_MODL_unite_bodies(cyl_jt1,cyl_jt2);  //布尔运算,求和